A simple random sample of 17 different cereals is obtained, and the sugar content (in grams of sugar per gram of cereal) is measured for each cereal selected. Those amounts have a mean of 0.292 gram and a standard deviation of 0.167 gram. Use a 0.05 significance level to test the claim of a cereal lobbyist that the mean for all cereals is less than 0.31 gram. Formulate the null and alternative hypotheses. Choose the correct answer below. OA. Ho: μ = 0.31 H₂: μ#0.31 C. Ho: μ = 0.31 Ha: μ<0.31 Find the test statistic. t= (Round to three decimal places as needed.) OB. Ho: μ = 0.31 Ha: μ>0.31 OD. Ho: μ<0.31 Ha: μ = 0.31

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**Sample Hypothesis Testing Using Cereal Sugar Content**

A simple random sample of 17 different cereals is obtained. The sugar content (in grams of sugar per gram of cereal) is measured for each selected cereal. These amounts have a mean of 0.292 grams and a standard deviation of 0.167 grams. We use a 0.05 significance level to test a cereal lobbyist's claim that the mean sugar content for all cereals is less than 0.31 grams.

**Formulate the Null and Alternative Hypotheses**

Select the correct answer:

- A. \( H_0: \mu = 0.31 \)  
  \( H_a: \mu \neq 0.31 \)

- B. \( H_0: \mu = 0.31 \)  
  \( H_a: \mu > 0.31 \)

- C. \( H_0: \mu = 0.31 \)  
  \( H_a: \mu < 0.31 \)  ← Correct

- D. \( H_0: \mu < 0.31 \)  
  \( H_a: \mu = 0.31 \)

**Find the Test Statistic**

Calculate the test statistic \( t \) and round to three decimal places as needed.

\[ t = \_\_ \]

This exercise aims to test whether the mean sugar content in cereals is statistically less than 0.31 grams based on the sample data provided. The hypothesis testing framework involves comparing the calculated test statistic to critical values derived from a t-distribution given the sample size and significance level.
Transcribed Image Text:**Sample Hypothesis Testing Using Cereal Sugar Content** A simple random sample of 17 different cereals is obtained. The sugar content (in grams of sugar per gram of cereal) is measured for each selected cereal. These amounts have a mean of 0.292 grams and a standard deviation of 0.167 grams. We use a 0.05 significance level to test a cereal lobbyist's claim that the mean sugar content for all cereals is less than 0.31 grams. **Formulate the Null and Alternative Hypotheses** Select the correct answer: - A. \( H_0: \mu = 0.31 \) \( H_a: \mu \neq 0.31 \) - B. \( H_0: \mu = 0.31 \) \( H_a: \mu > 0.31 \) - C. \( H_0: \mu = 0.31 \) \( H_a: \mu < 0.31 \) ← Correct - D. \( H_0: \mu < 0.31 \) \( H_a: \mu = 0.31 \) **Find the Test Statistic** Calculate the test statistic \( t \) and round to three decimal places as needed. \[ t = \_\_ \] This exercise aims to test whether the mean sugar content in cereals is statistically less than 0.31 grams based on the sample data provided. The hypothesis testing framework involves comparing the calculated test statistic to critical values derived from a t-distribution given the sample size and significance level.
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