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Find a mole of :
H2SO4 (15 ml 3.0 M)
NaOH ( 18 mL 2.5 M)
Acetic anhydride (3.0 mL)
Step by step
Solved in 2 steps
- how many equivalents of 6M NaOH would you add (in other words, what molar ratio of 6M NaOH to triester do you need) so that the reaction runs as pictured?4. How much 0.20 M H3PO4 is needed to react with 100.0 mL of 0.10 M NaOH? H3PO4 + 3 NaOH --> Na3PO4 + 3 H2OHow do you Prepare 500 mL of 0.025 M Na2S2O2•5H2O?
- What are the Volumes of HCl from the 3 Trials?a 310.0 mL of 0.52 M NaOH m(NaOH) = m(H2O) = | Submit b 1.3 L of 6.6E-2 M Ba(OH)2 m(Ba(OH)2) = m(H2O) = | 780.0 mL of 9.0E-2 M KOH m(KOH) = m(H2O) = d 2.0 L of 0.34 M sodium acetate m(CH;COONA) = | m(H2O) =The number of moles produced in H2Oin reaction of 100 mL 1.0M HCl & 100 mL 1.0 M NaOH (Show calculations)
- Esc 2 What is the concentration of a solution made with 0.245 moles of KOH in 400.0 mL of solution? 1 F1 ! + A 4x Q N Bi F2 NO @ 2 W S Alt X F3 # 3 JL E F4 D 14 C $ 4 F5 R F ► 11 % 5 V F6 A T G ^ (0 F7 6 B Y H F8 & 7 2 DELL U N F9 * S 8 J F10 ( 3 9 F11 J K O A ) O F12 L Alt PrtScr P 7 BU +/- 4 1 Inse- [ VER ?Calculate the number of mercury (Hg) atoms in an aqueous solution with a volume of 1.00 L and a concentration of 1.0 ppb.What is the concentration of a solution made by diluting 85 mL of 6.0 M HCl to a final volume of 750 mL? concentration: J $ 4 R F F4 V % 5 T G B ^ 6 MacBook Air Y H & 7 N B U J * 8 M MOSISO DII FB K 9 H DD FO O ) O L command A F10 P A. 1. option 4 F11 L ? + f F12 M delete ret
- How much Na2SO4 is required to precipitate 2.50 g of Ba(NO3)2 in the form of BaSO4? AW: Ba = 137.33, Na = 22.99, S= 32.07, N = 14.01, O = 16.00 O 2.50 g O 0.0176 mole O 0.0191 mole O 1.36 gData of HCl Trial 1: volume of HCl =0.82l Volume of NaOH =22.1ml Trial 2: volume of HCl=0.821ml Volume of NaOH = 22.2ml Trial 3: volume of HCl= 0.821ml Volume NaOH = 22.7ml 1) calculate the molarity of HCl for each trial and find the average molarity.Aa.4.
