What are the Volumes of HCl from the 3 Trials? **Rough Titration Results**| | Rough Titration ||--------------------------------|-----------------|| a. Volume HCl (mL) | 25.00 || b. Initial buret reading (mL) | 0.00 || c. Final buret reading (mL) | 25.40 || d. Volume of NaOH used (mL) | 25.40 |**Titration Data**| | Trial 1 | Trial 2 | Trial 3 ||------------------------------|---------|---------|---------|| 1. Volume HCl (mL) | 25.00 | 25.00 | 25.00 || 2. Initial buret reading (mL)| 0.00 | 0.00 | 0.00 || 3. Final buret reading (mL) | 24.20 | 24.60 | 24.70 |Both tables provide information on the titration process:- **Rough Titration Results**: This includes initial and final buret readings and helps calculate the volume of NaOH used to reach the endpoint of the titration. - **Titration Data**: The table displays three different trials with consistent initial readings and varying final readings, showing the slight variation in NaOH volume required for each trial.These tables help in understanding the precision and accuracy of the titration process. The image displays a table format with results from three trials of a chemical experiment. The table includes measurements and calculations for solutions involving NaOH and HCl.**Part 3 of 10**1. **Volume NaOH Used (L)** - *(1 L = 1000 mL)* - Trial 1: 0.02420 ✓ - Trial 2: 0.02460 ✓ - Trial 3: 0.02470 ✓**Part 4 of 10**2. **Moles NaOH (mols)** - *(The concentration of the NaOH solution is 0.1104 M)* - Trial 1: 2.671 ✗ - Trial 2: 0.00271584 ✓ - Trial 3: 0.00272688 ✓**Part 5 of 10**3. **Moles HCl (mols)** - *(Use the balanced equation to create a mole ratio to convert moles of NaOH to moles of HCl)* - Trial 1: 0.00267168 ✓ - Trial 2: 0.00271584 ✓ - Trial 3: 0.00272688 ✓**Part 6 of 10**4. **Volume of HCl (L)** - *(1 L = 1000 mL)* - Trial 1: [Empty] - Trial 2: [Empty] - Trial 3: [Empty]The table indicates checks for correct values with "✓" and an incorrect value with "✗". Moles of NaOH are calculated using its given concentration, while moles of HCl are derived using the stoichiometric ratios from the balanced chemical equation.

Equation NaOH(aq) + HCl (aq) ——> NaCl (aq) + H2O(l) Molarity = no. of moles / volume (Lt)

Volume HCl (mL) 25.00 а. 0.00 b. Initial buret reading (mL) 25.40 c. Final buret reading (mL) 25.40 d. Volume of NaOH used (mL) Titration Data Trial 1 Trial 2 Trial 3 1. Volume HCl (mL) 25.00 25.00 25.00 0.00 0.00 0.00 2. Initial buret reading (mL) 24.20 24.60 |24.70 3. Final buret reading (mL) Part 2 of 10

Volume HCl (mL) 25.00 а. 0.00 b. Initial buret reading (mL) 25.40 c. Final buret reading (mL) 25.40 d. Volume of NaOH used (mL) Titration Data Trial 1 Trial 2 Trial 3 1. Volume HCl (mL) 25.00 25.00 25.00 0.00 0.00 0.00 2. Initial buret reading (mL) 24.20 24.60 |24.70 3. Final buret reading (mL) Part 2 of 10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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