A traffic coordinator for a community wishes to determine whether or not there is any difference in theaverage age of female and male drivers involved in rear-end accidents. The hypothesis test is: Ho:41 = 42(no difference in mean age)10H1:(mean age is different) A random sample of males and females involved in rear-end accidentsresults in the following Minitab summary:NMEANMEDIANTRMEANSTDEVSE MEANFEMALES3323.9120.0023.389.771.70MALES3828.8728.5028.449.671.57а).What is the value of the test statistic?Appropriate test:Test statistic =b).What is the decision rule at the 0.025 level of significance?с).What is the conclusion?

Suppose the sample xi, (i=1,2,...,n1) of size n1 has been drawn from the population with mean μ1 and…

Answered: FEMALES 33 23.91 20.00 23.38 9.77 1.70…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average retirement age in America is 63 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 65, 59, 58, 62, 60, 62, 58, 69, 59, 62, 71, 68, 76, 57 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: H₁: O # O O 63 c. The test statistic to d. The p-value = e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... Add Work 63 > Next Question O The data suggest the population mean retirement age for small business owners is not significantly different from 63 at a = 0.05, so there is insufficient evidence to conclude that the population mean retirement age for small business owners is different…
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The average American gets a haircut every 43 days. Is the average different for college students? The data below shows the results of a survey of 11 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 32, 46, 49, 45, 50, 49, 43, 45, 38, 46, 42 What can be concluded at the the a =0.01 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Họ: ? Select an answer v H. Select an answer Y C. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value - (Please show your answer to 3 decimal places.) e. The p-value is 2 f. Based on this, we should Select an answer the null hypothesis, g. Thus, the final conclusion is that, The data suggest the populaton mean is significantly different from 43 ata = 0.01, so there is fficient evidence tr conrlide that -he nonulation.
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Median household income in a particular county is $46,250. A researcher is interested to see whether students at the county community college have a median household income lower than the county overalI. She selects 15 students at random and determines that 12 have a household income below the county median, one has an income equal to the county median, and two have a household income above the county median. She wishes to conduct her test using the 0.05 significance level. What is the decision rule? Multiple Choice Reject Ho if the number above the median is <3 or 28. Reject Ho if the number above the median is <3. Reject Ho if the number above the median is <2 or 210. Reject Ho if the number above the median is <2.
Find the test statistic Find the critical value What is the conclusion

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FEMALES 33 23.91 20.00 23.38 9.77 1.70 MALES 38 28.87 28.50 28.44 9.67 1.57 а). What is the value of the test statistic? Appropriate test: Test statistic= b). What is the decision rule at the 0.025 level of significance?