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F2 Y B V 5 4 3 F1 X F3 → The given forces are F₁ = 20 kN, F2= 28 kN, and F3 = 61 kN, with given ratio for F₁ and angles of B = 51° and y = 67°. Find the resultant force. First in Cartesian Vector Notation: FR = 2 + j) kN Then, find the magnitude and direction: magnitude in kN: kN conventional direction (counter clockwise from positive X axis) in degrees: deg

F2 Y B V 5 4 3 F1 X F3 → The given forces are F₁ = 20 kN, F2= 28 kN, and F3 = 61 kN, with given ratio for F₁ and angles of B = 51° and y = 67°. Find the resultant force. First in Cartesian Vector Notation: FR = 2 + j) kN Then, find the magnitude and direction: magnitude in kN: kN conventional direction (counter clockwise from positive X axis) in degrees: deg

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
ChapterB: Graphical Analysis Of Planar Trusses
Section: Chapter Questions
Problem 8P
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F2 Y B V 5 4 3 F1 X F3 → The given forces are F₁ = 20 kN, F2= 28 kN, and F3 = 61 kN, with given ratio for F₁ and angles of B = 51° and y = 67°. Find the resultant force. First in Cartesian Vector Notation: FR = 2 + j) kN Then, find the magnitude and direction: magnitude in kN: kN conventional direction (counter clockwise from positive X axis) in degrees: deg
Transcribed Image Text:F2 Y B V 5 4 3 F1 X F3 → The given forces are F₁ = 20 kN, F2= 28 kN, and F3 = 61 kN, with given ratio for F₁ and angles of B = 51° and y = 67°. Find the resultant force. First in Cartesian Vector Notation: FR = 2 + j) kN Then, find the magnitude and direction: magnitude in kN: kN conventional direction (counter clockwise from positive X axis) in degrees: deg
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