ExpressionsExplain your answers below1. int x = 2 + 0.1;int y = 3 + 0.9;x = y;Explanation:%3Dx =y =2. int xint yx x + y / x;Explanation:2;= 3;x =y =3. int x = 2;3;int yx = 5 - x * y - 1;Explanation:y =4. int x = 2;int y = 3;x (5 + x) * y - 1;Explanation:x =y =5. int x = 2;int y = 3;x = (5 + x) * (y - 1);Explanation:%3Dy =6. int x = 1 * 1 / 10 * 100;Explanation:X =y =

I give the answer with proper explanation as well as their screenshot of the output as code

Expressions Explain your answers below 1. int x = 2 + 0.1; int y = 3 + 0.9; x = y; Explanation: x = y = = 2; int y = 3; x x + y / x; Explanation: 2. int x %3D x = y = 3. int x = 2; int y = 3; x = 5 - x *y -1; Explanation: %3D X = y = 4. int x = 2; int y = 3; x = (5 + x) *y - 1; Explanation: x = y 5. int x = 2; int y = 3; x = (5 + x) * (y - 1); Explanation: y = 6. int x =1 * 1/10 * 100; Explanation: X = y =

Expressions Explain your answers below 1. int x = 2 + 0.1; int y = 3 + 0.9; x = y; Explanation: x = y = = 2; int y = 3; x x + y / x; Explanation: 2. int x %3D x = y = 3. int x = 2; int y = 3; x = 5 - x y -1; Explanation: %3D X = y = 4. int x = 2; int y = 3; x = (5 + x) y - 1; Explanation: x = y 5. int x = 2; int y = 3; x = (5 + x) * (y - 1); Explanation: y = 6. int x =1 * 1/10 * 100; Explanation: X = y =

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Q: #include int main() float Bread = 1.09, Water = 2.18, Banana = 1.00, Meat = 7.99; // Unit for bread…

A: Solution: These two line are: //line-1 printf("You have %d loaves of bread, %d bottles of…

Q: in this code, the integer on each line shows the line number that is not part of code: what is he…

A: Answer:- Variable x, y and z are the local variables of sum function. Here parameters are also…

Q: One Computer Science program uses the following rules tor CS course placement: 1. if the CS AP score…

A: Objective: This program determines CS placement for students depending on certain given rules. The…

Q: #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0;…

A: The given c program is to calculate the change. This program prompts the user to enter the value…

Q: If the following code, what will be the variable "value" equal to when y=2 is being executed: def…

A: The question has been answered in step2

Q: ASSIGNMENT-1QUANTITATIVE METHODS(STAT-201)Student Full Name:Student ID:CRN No.:Note: 1. All the…

A: NOTE: This is a multipart question based problem. As per company guidelines only first three parts…

Q: a = CalSomething (a, CalSomething (a), y); %3D

A: Assuming that we need to fill in the blanks before a in the second image, that means we need to…

Q: Given two input integers for an arrow body and arrowhead (respectively), print a right-facing arrow.…

A: Start the program execution.Declare two integer variables baseInt and headInt.Prompt the user to…

Q: What is the final value of y? int x = 4; int y = 6; if (x < 10) { if (y < 5) { y = y + 1; } } else {…

A: The provided C code snippet poses an intriguing programming puzzle, inviting to decipher the final…

Q: Use the pseudocode methods below to answer the questions starting on the next page. FIRST…

A: There are three Pseudo code given. answers for the given question in step 2.

Q: Te a program This calculator is limited to the following functions: ➤ Addition Subtraction…

A: This program is a simple calculator simulation implemented in Java. It allows the user to perform…

Q: two integer numbers as inputs

A: Given :- In the above question, the statement is mention in the above given question Need to write…

Q: #import math library #define functions #return type: float #Parameters: 2 floats(l and w) #This…

A: #import math libraryimport math#define functions #return type: float#Parameters: 2 floats(l and…

Q: #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0;…

A: The algorithm to calculate the amount of change returned is given below: - Algorithm: - Step1:…

Q: public class MysteryReturn 2 { 3 public static void main(String[] args) 4 { 5 int x = 1; 6 int y =…

A: Please find the answer below :

Q: public static int test1(int x1, int x2){ 8 9 if(x1==0){ 10 x1=10;…

A: The provided code is a Java program that consists of several methods, including test1, test2, input,…

Q: Use the pseudocode methods below to answer the questions starting on the next page. FIRST…

A: Given: From the given pseudocode methods, we have to choose which method corresponds to each of the…

Q: int pertambahan(int pilihan, int now){ int result; result =pilihan + now; return result; } int…

A: Given Program: #include <stdio.h> int pertambahan(int pilihan, int now){ int result; result…

Q: The following statement, x = 5; is the first assignment of x within a valid sketch. It can be…

A: Answer :- option D) an initialization

Q: First-Player Advantage Pig is a folk jeopardy dice game with simple rules: Two players race to reach…

A: To solve this problem, we need to simulate a large number of games and count the number of times the…

Q: Question1 Write a procedure to find the maximum of three numbers. Procedure specification: •…

A: Detailed explanation: 1. Declaration of max3 Procedure:We define a procedure called max3 that takes…

Q: Part 3: Looping while(x<y) { If(z<0){ x=x+a; } Else{ x=x+z; z= -z } x=x+1; }…

A: The while loop is a fundamental control structure in programming that allows a block of code to be…

Q: #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0;…

A: What works: Input works if it is in the range of 5 and 95 included 5 and 95. Input works if it is…

Q: 13: Evaluate (or (= 50 13) (> 16 88)) 00 #T 1 This expression would produce an error message when…

A: Answer 13: after run value is NIL.#F so correct option is e Answer 14: after run it in lisp so…

Q: int stop = 6; int num =6; int count=0; for(int i = stop; i >0; i-=2) { num += i;…

A: The given code is in Java.

Question

Expressions
Explain your answers below
1. int x = 2 + 0.1;
int y = 3 + 0.9;
x = y;
Explanation:
%3D
x =
y =
2. int x
int y
x x + y / x;
Explanation:
2;
= 3;
x =
y =
3. int x = 2;
3;
int y
x = 5 - x * y - 1;
Explanation:
y =
4. int x = 2;
int y = 3;
x (5 + x) * y - 1;
Explanation:
x =
y =
5. int x = 2;
int y = 3;
x = (5 + x) * (y - 1);
Explanation:
%3D
y =
6. int x = 1 * 1 / 10 * 100;
Explanation:
X =
y =

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

explanation with answer

1screenshot

2screenshot

3screenshot

4screenshot

5screenshot

6screenshot

Step by step

Solved in 8 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

def area(side1, side2): return side1 * side2s1 = 12s2 = 6Identify the statements that correctly call the area function. Select ALL that apply. Question options: area(s1,s2) answer = area(s1,s2) print(f'The area is {area(s1,s2)}') result = area(side1,side2)
Directions: The question or incomplete statement below is followed by four suggested answers or completions. Select the one that is best in each case. A student wrote the following code for a guessing game. Line 1: secretNumber RANDOM (1, 100) Line 2: win ← false Line 3: REPEAT UNTIL (win) Line 4: ( Line 5: DISPLAY ("Guess a number.") Line 6: guess INPUT ( ) Line 7: IF (guess = secretNumber) Line 8: ( Line 9: DISPLAY ("You got it right!") Line 10: } Line 11: Line 12: Line 13: ( ELSE IF (guess > secretNumber) Line 14: ( Line 15: DISPLAY ("Your guess is too high.") Line 16: } Line 17: ELSE Line 18: ( Line 19: DISPLAY ("Your guess is too low.") Line 20: } Line 21: } Line 22: } While debugging the code, the student realizes that the loop never terminates. The student plans to insert the instruction win true somewhere in the code. Where could win true be inserted so that the code segment works as intended? Between line 6 and line 7 Between line 9 and line 10 Between line 20 and 21 Between…
Given code: int s=0; for ( int i=1; i<5; i++ ){ s = s + i ; } Which one is correct, after running the code. Group of answer choices s=1 s=15 s=10 s=5
in this code, the integer on each line shows the line number that is not part of code: what are the parameters of sum: ____ 1 public static int sum(int x, int y){ 2 int z = x +y; 3 return z; 4 } 5 public static void main(String[] args){ 6 … 7 sum(a+2, b); 8 … 9 }
this is the code: const int BLED=9; //Blue LED on Pin 9const int GLED=10; //Green LED on Pin 10const int RLED=11; //Red LED on Pin 11const int Switch=2; //The Button is connected to pin 2boolean lastSwitch = LOW; //Last Button Stateboolean currentSwitch = LOW; //Current Button Stateint ledMode = 0; //Cycle between LED statesboolean ledOn = false;void setup(){ pinMode (BLED, OUTPUT); //Set Blue LED as OutputpinMode (GLED, OUTPUT); //Set Green LED as OutputpinMode (RLED, OUTPUT); //Set Red LED as OutputpinMode (Switch, INPUT); //Set button as input (not required)}}/** LED Mode Selection Pass a number for the LED state and set it accordingly.*/void setMode(int mode){//RED if (mode == 1) { digitalWrite(RLED, HIGH); digitalWrite(GLED, LOW); digitalWrite(BLED, LOW);} //GREENelse if (mode == 2){ digitalWrite(RLED, LOW); digitalWrite(GLED, HIGH); digitalWrite(BLED, LOW); }//BLUE else if (mode == 3) { digitalWrite(RLED, LOW); digitalWrite(GLED, LOW); digitalWrite(BLED, HIGH); } //PURPLE…
tranlate source program in the picture into quadruples tranlate source program in the picture into quadruples tranlate source program in the picture into quadruples
#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…