This is a practice problem. Experiment 1. Assay of Hydrogen Peroxide SolutionPrinciple:Direct permanganometryThe percentage purity of hydrogen peroxide set by the USP is 2.5 – 3.5 g/100 ml.Procedure (whole formulation; three trials)1. Pipet 2 milliters of hydrogen peroxide solution into a suitable flask containing 20 militers of water. (H;O2 p = 1.45 g/ml)2. Add 20 milliliters of diluted sulfuric acid3. Titrate with 0.1 N potassium permanganate solution, wherefor each trial is provided in the table below).ml was consumed (the theoretical volume consumedNI ml x meg4. Calculate the percentage purity of the sample, using the formula:% =x 100 %wtReaction (fill in the coefficients on the blank spaces):_H2O2 +_ KMNO4 +_ H2SO4 → _O2 +_ MNSO4 + _ K2SO4 + _ H2oOxidation: Reducing Agent H2*1022O20 + 2H +_e-Reduction: Oxidizing Agent Mn*O2 + 8H +.e- Mn*7 + 4H2ONumber of e- gain/loss of oxygen is; which is the factor hydrogen peroxide-Data and Results:Trial 1Trial 2Trial 3Weight of H2O2Volume of KMNO.Percentage purityAverage percentage purity43 ml42.8 ml43.5 mlCalculation and ConclusionOn space below, solve the titer value and average percentage purity of the sample then interpret.

Given: Volume of H2O2 = 2.0 mL density of = 1.45 g/mL Concentration of KMnO4 = 0.1 N

Principle: Direct permanganometry The percentage purity of hydrogen peroxide set by the USP is 2.5 – 3.5 g/100 ml. Procedure (whole formulation; three trials) 1. Pipet 2 milliters of hydrogen peroxide solution into a suitable flask containing 20 milliters of water. (H;O2 p = 1.45 g/ml) 2. Add 20 milliters of diluted sulfuric acid 3. Titrate with 0.1 N potassium permanganate solution, wheremi was consumed (the theoretical volume consumed for each trial is provided in the table below). 4. Calculate the percentage purity of the sample, using the formula: NI mi x meg 100 % % = Reaction (fil in the coefficients on the blank spaces): _H2O2 +_ KMNO4 + _ H;SO4 →_ O2 + _ MNSO, + _ K2SO4 + _ H20 Oxidation: Reducing Agent H2*1022 → 0,0 + 2H +_• Reduction: Oxidizing Agent Mn*70r² + 8H + _* → Mn*7 + 4H2O * Number of e- gain/loss of oxygen is, ; which is the factor hydrogen peroxide Data and Results: Trial 1 Trial 2 Trial 3 Weight of H:Oa Volume of KMNO, Percentage purity Average percentage purity 43 ml 42.8 ml 43.5 ml Calculation and Conclusion

Principle: Direct permanganometry The percentage purity of hydrogen peroxide set by the USP is 2.5 – 3.5 g/100 ml. Procedure (whole formulation; three trials) 1. Pipet 2 milliters of hydrogen peroxide solution into a suitable flask containing 20 milliters of water. (H;O2 p = 1.45 g/ml) 2. Add 20 milliters of diluted sulfuric acid 3. Titrate with 0.1 N potassium permanganate solution, wheremi was consumed (the theoretical volume consumed for each trial is provided in the table below). 4. Calculate the percentage purity of the sample, using the formula: NI mi x meg 100 % % = Reaction (fil in the coefficients on the blank spaces): _H2O2 +_ KMNO4 + _ H;SO4 →_ O2 + _ MNSO, + _ K2SO4 + _ H20 Oxidation: Reducing Agent H21022 → 0,0 + 2H +_• Reduction: Oxidizing Agent Mn70r² + 8H + _* → Mn7 + 4H2O Number of e- gain/loss of oxygen is, ; which is the factor hydrogen peroxide Data and Results: Trial 1 Trial 2 Trial 3 Weight of H:Oa Volume of KMNO, Percentage purity Average percentage purity 43 ml 42.8 ml 43.5 ml Calculation and Conclusion

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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N CHEM 121A.1002 General Chemi X Course Home b Search results for 'Consider the b + A openvellum.ecollege.com/course.html?courseld=16418591&OpenVellumHMAC=49dc8320dbb0d06efbbd270f8450809f#10001 Course Home Problem 5.84 - Enhanced - with Feedback Item 11 > Syllabus II Review | Constants | Periodic Table Scores Use bond enthalpies in the table below to estimate AH for each of the following reactions. Pearson eText Part A Average bond enthalpy (kJ/mol) Study Area C-H: 413 N-–H: 391 0-H: 463 F-F: 155 C-C: 348 N-N: 163 0-0: 146 Br Br Document Sharing Br- С-Н + СІ—CІ Br С-—СІ + CІ—Н C=C: 614 N-–0: 201 0=0: 495 Cl-F: 253 C-N: 293 N-F: 272 0-F: 190 Cl-Cl: 242 User Settings Br Br C-0: 358 N-Cl: 200 0-Cl: 203 Br-F: 237 C=0: 799 N-Br: 243 0-I: C-F: 485 H-H: 436 Course Tools > 234 Br-Cl: 218 Express your answer in kilojoules to three significant figures. Br-Br: 193 C-Cl: 328 H-F: 567 C-Br: 276 H–Cl: 431 I-Cl: 208 C-I: 240 H-Br: 366 I-Br: 175 ΔΗ kJ H-I: 299 I-I: 151 Submit Request Answer A OneDrive…
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