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Conc. NaOH soln., M (listed on bottle) 0.1 M Part A. Standardization of a sodium hydroxide solution. reading (ml. Na Mass of KHP used (g) .55 g Final buret reading (mL NaOH) 31.6 mL .5 mL Initial buret reading (mL NaOH) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Molarity of NaOH 31.1mL 1 204.999 .55g ImL Sample calculations for molarity of NaOH solution: Trial 2 56 g 29.7ml .8mL Trial 3 .55 g 27.9ml 1.1mL 28.9mL 26.8ml : in 50mL water 204.44 g/m² MHCL UNCL M/molarity = mol/L Average molarity of NaOH solution: You will be using the average molarity of the NaOH solution in calculations of the molarity of the unknown acid, in part B. Мнсь mol Hel W Hel Sample calculations for moles of KHP used: Mol HCl = MHCL H HCL .00156 mol KHP .00269 mol 50 mL =M NOOH = .0000S

Conc. NaOH soln., M (listed on bottle) 0.1 M Part A. Standardization of a sodium hydroxide solution. reading (ml. Na Mass of KHP used (g) .55 g Final buret reading (mL NaOH) 31.6 mL .5 mL Initial buret reading (mL NaOH) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Molarity of NaOH 31.1mL 1 204.999 .55g ImL Sample calculations for molarity of NaOH solution: Trial 2 56 g 29.7ml .8mL Trial 3 .55 g 27.9ml 1.1mL 28.9mL 26.8ml : in 50mL water 204.44 g/m² MHCL UNCL M/molarity = mol/L Average molarity of NaOH solution: You will be using the average molarity of the NaOH solution in calculations of the molarity of the unknown acid, in part B. Мнсь mol Hel W Hel Sample calculations for moles of KHP used: Mol HCl = MHCL H HCL .00156 mol KHP .00269 mol 50 mL =M NOOH = .0000S

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ignore my calculations that are already on there, but I'm struggling on this one and a step by step would really help me out. Thank you!

Conc. NaOH soln., M (listed on bottle) Part A. Standardization of a sodium hydroxide solution. ading (ml. Mass of KHP used (g) Liter Initial buret reading (mL NaOH) Volume of NaOH used (mL) 0.1 M Final buret reading (mL NaOH) 31.6 Moles of NaOH used Molarity of NaOH Trial 1 .55 g 3.1.6 mL mL .5mL 31.1mL Sample calculations for molarity of NaOH solution: . I mol ,00156 mo • SSg I mol 201.499 .55g Im L Trial 2 = .00269 mol Trial 3 .55 .56 g 29.7ml 27.9m² 204.44 g/mol M. .8mL g 1.1mL 28.9mL 26.8ml M/molarity = mol/L Average molarity of NaOH solution: You will be using the average molarity of the NaOH solution in calculations of the molarity of the unknown acid, in part B. mol Hel W Hel Sample calculations for moles of KHP used: .00156 mol KHP M HCL in 50mL water .00269 mol 50mL Gr M₁ V₁₂₁=M V HCL HCL 1 mm L .00156 molKHP used Mol HCI = MHCL = MHCL HCL V. 31.1mb.005381 ml NOOH NooH = .00005381 mol/mL = .00167 M = .001$$$ m S = .0051442 w
Transcribed Image Text:Conc. NaOH soln., M (listed on bottle) Part A. Standardization of a sodium hydroxide solution. ading (ml. Mass of KHP used (g) Liter Initial buret reading (mL NaOH) Volume of NaOH used (mL) 0.1 M Final buret reading (mL NaOH) 31.6 Moles of NaOH used Molarity of NaOH Trial 1 .55 g 3.1.6 mL mL .5mL 31.1mL Sample calculations for molarity of NaOH solution: . I mol ,00156 mo • SSg I mol 201.499 .55g Im L Trial 2 = .00269 mol Trial 3 .55 .56 g 29.7ml 27.9m² 204.44 g/mol M. .8mL g 1.1mL 28.9mL 26.8ml M/molarity = mol/L Average molarity of NaOH solution: You will be using the average molarity of the NaOH solution in calculations of the molarity of the unknown acid, in part B. mol Hel W Hel Sample calculations for moles of KHP used: .00156 mol KHP M HCL in 50mL water .00269 mol 50mL Gr M₁ V₁₂₁=M V HCL HCL 1 mm L .00156 molKHP used Mol HCI = MHCL = MHCL HCL V. 31.1mb.005381 ml NOOH NooH = .00005381 mol/mL = .00167 M = .001$$$ m S = .0051442 w
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