Exercise 1: While Loop High-level code // determines the power of x such that 2x = 128 int pow = 1; int x = 0; while (pow != 128) { pow = x = x + 1; pow * 2; MIPS assembly code # $s0 = pow, $s1 = x Assembly tests for the opposite case (pow == 128)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please write the assembly tests for the opposite cases as mentioned at the bottom of the submitted pictures.

Exercise 1: While Loop
High-level code
// determines the power of x such that 2x = 128
int pow = 1;
int x = 0;
%3D
while (pow != 128)
{
pow = pow * 2;
X = X + 1;
MIPS assembly code
# $$0 = pow, $s1 = x
Assembly tests for the opposite case (pow == 128)
Transcribed Image Text:Exercise 1: While Loop High-level code // determines the power of x such that 2x = 128 int pow = 1; int x = 0; %3D while (pow != 128) { pow = pow * 2; X = X + 1; MIPS assembly code # $$0 = pow, $s1 = x Assembly tests for the opposite case (pow == 128)
Exercise 1: For Loop
High-level code
// add the numbers from 0 to9
int sum = 0;
int i;
for (i = 0; i != 10; i = i + 1)
{
sum = sum + i;
}
MIPS assembly code
# $$0 = i, $s1 = sum
%3D
%3D
Assembly tests for the opposite case (i == 10)
Transcribed Image Text:Exercise 1: For Loop High-level code // add the numbers from 0 to9 int sum = 0; int i; for (i = 0; i != 10; i = i + 1) { sum = sum + i; } MIPS assembly code # $$0 = i, $s1 = sum %3D %3D Assembly tests for the opposite case (i == 10)
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