Example 12.12 Consider the unbalanced A-A circuit in Fig. 12.30. Use PSpice to find the generator current Lab, the line current IB, and the phase current Inc 12.9 PSpice for Three-Phase Circuits 531 a ww A 202 m 15 Ω 208/10° V € 502 2018/130 V b ww 202 m j5Q B -1402 208-110° V 130 Ω 202 j5Q ww -m C Figure 12.30 For Example 12.12.
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- The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load under sinusoidal-steady-state excitation. is (a) Nonzero constant (b) Zero (c) Containing double-frequency componentsConsider a 10 kVA, 200/400 V, 50 HZ: single-phase tranformer has the folloving test results:0.C. test: 200 V, 0.6A, 63 W (L.V.side)S.C. test : 20 V, 25A, 85 W (H.V. side)Deternine:i- The eficiengy at 75 % offiull-load at 0.9 leading power factor.ii -The secondary terminal voltage on fill-load at tunity power factonThe three-wire 230/460 V rms 60 Hz system, shown in figure 12.29, supplies power to three loads: the AN load demands a complex power of 10 /40° kVA, the NB load draws 8 /10° kVA, and the AB load requires 4 /-80° kVA. Determine the two currents, the line and the neutral.
- Solve 86.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%1980628cmid 11616 For reactive load, the power factor is equal to Select one: O a. 1 O b. 90 O c. 2 O d.0 If the voltage V, = 800 mV, then the current flowing in the primary winding Ip is: j2on Select one: O a. None of these O b. l, =40<0° mA O c.l, = 0.320<90° A O d. Ip =320<-90° mA if a Load absorbs an average power of 8 kW at a lagging power factor of 0.5 Select one: O a. -8000 + j13856.4 VA O b. None of these O c. 8000 - j13856.4 VA O d. 8000 - j13856.4 VA estion-299141-3 freactive power is
- A single-phase power system is shown as the equivalent circuit below. The system has a 480V generator connected to an ideal 1:10 step-up transformer (no losses), a transmission line, an ideal 20:1 step-down transformer and a load all in series as shown. The resistance of the transmission line is 20 S2 and the reactance j60 , a load is connected to the system with an impedance of 10/30° №. For the analysis of the system, use base values of 10 kVA and 480 V at the generator, find (a) per unit values of all impedances, (b) per unit current, (c) load power (W), (d) power loss (W). NG 480 20⁰ V 10 kVA Zone 1 1:10 20 Ω j60 Ω ZL Zone 2 20:1 ILoad Zone 3 ZLoad 10/30° ΩThe total power drawn by the two-impedance load in parallel is 26kW at 0.98 power factor lagging, it is being supplied by a 230-volts AC source. One of the loads (Load 1) takes 16kVA at 0.77 power factor lagging. What is the reactive power of the unknown impedance (Load 2)?Let a series RLC network be connected to a source voltage V, drawing a current I. (a) In terms of the load impedance Z=ZZ, find expressions for P and Q, from complex power considerations. (b) Express p(t) in terms of P and Q, by choosing i(t)=2Icost. (c) For the case of Z=R+jL+1/jC, interpret the result of part (b) in terms of P,QL, and Qc. In particular, if 2LC=1, when the inductive and capacitive reactances cancel, comment on what happens.
- (b) A symmetrical delta-connected 415V three-phase supply is feed to an asymmetrical delta- connected load as shown in Figure Q2(b). Assume that it is a RYB sequence. The impedances of the load are ZRY = 50 +j50 Q , ZYB = 150 + j0 Q and ZBR= 50 – j50 N. (i) Determine and draw the phasor diagram of phase currents in the load. (ii) Determine and draw the phasor diagram of line currents in the system.2. A single-phase a.c. distributor AB is fed from end A and has a total impedance of (0-2 +j03) ohm. At the far end, the voltage VR = 240 V and the current is 100 A at a p.f. of 0-8 lagging. At the mid-point M, a current of 100 A is tapped at a p.f. of 0-6 lagging with reference to the voltage Vy at the mid-point. Calculate the supply voltage V and phase angle between V and Vg- [292 V, 2-6°] T 40 AA parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit