Ex (N/C) The graph shows the electric field as a function of position in a particular region of space. If Exs = 800 difference between x = 0.00 m and x = 6.00 m? V Exs -Exs 0 2 3 4 5 6 x (m) V m , what is the potential
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Q: The graph shows the electric field as a function of position in a particular region of space. If Exs…
A: thank you
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A: The electric potential versus distance graph is shown below.
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A: Answer is uploaded in step 2.
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A: Q1 = + 3.45 × 10-⁶ C Q2 = + 7.65 × 10-⁶ C Q3 = - 1.15 × 10-⁶ C r = 1.35 m
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A: Electrostatic.
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- A From Equation 25.6, we have the following. AV = -Ed = -(7.2 × 104 v/m)(0.60 m) = B V From Equation 25.3, we have the following. AU = qAV = eAV = (1.6 x 10-19 C)(AV) | The negative sign means that the potential energy of the system decreases as the proton moves in the direction of the electric field. This decrease is consistent with the conservation of energy in an isolated system: as the proton accelerates in the direction of the field, it gains kinetic energy and at the same time the system loses electric potential energy. The increase in kinetic energy of a charged particle in an electric field is exploited in many devices, including electron guns for TV picture tubes and particle accelerators for research in particle physics. You can predict and observe the speed of the proton as it arrives at the negative plate for random values of the electric field using this Interactive Example. Hints: Getting Started | I'm Stuck Exercise 25.2 For the previous example, apply the principle of…At locations A and B, the electric potential has the values VA = 1.59 V and VB = 5.87 V, respectively. A proton released from rest at one of these locations passes through the other location. From which location was the proton released? A В What is its speed when it passes through the other location? 2.93 x104 speed: m/s IncorrectAn electron is accelerated from rest in a small particle accelerator via a constant electric field E = 10.5 *1015 N/m over a distance of 15.5m. a) How much work does the electric field do on the electron over this distance? b) What is the electric potential difference between the electron's initial location and final location? c) What is the final kinetic energy of the electron?
- A potential difference of 106 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative relative to the outer surface. How much work is required to eject a positive sodium ion (Na+) from the interior of the cell? JYou have a parallel-plate 5.81 × 10-° F capacitor that is charged to 0.00949 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.01 × 10-º F. How much work W do you perform in this process? W = JDuring a particular thunderstorm, the electric potential between a cloud and the ground is Valoud - Vground = 2.7 x 10 V, with the cloud being at the higher potential. What is the change in an electron's potential energy when the electron moves from the ground to the cloud?
- An air-filled parallel-plate capacitor has plates of area 2.60 cm² separated by 2.50 mm. The capacitor is connected to a 15.0-V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? V/mWhen an electron moves from A to B along an electric field line in the figure, the electric field does 4.52 × 10-19 J of work on it. What are the electric potential differences (a) VB - VA, (b)Vc - VA, and (c)VC - VB? Electric field line EquipotentialsWhen an electron moves from A to B along an electric field line in the figure, the electric field does 5.70 × 10-19 J of work on it. What are the electric potential differences (a)VB - VA, (b)Vc - VA, and (c)Vc - VB? (a) Number i (b) Number (c) Number i Electric field line Units Units Units Equipotentials
- A (4.000x10^2) µF capacitor is fully-charged when it has (9.6x10^-3) C on its plates. What is the potential difference across the plates of the capacitor? Give your answer in V using scientific notation.Consider the capacitor below, that is not connected to anything. The capacitor has a dielectric between its plates initially. The dielectric is slowly pulled out from between the plates. As that happens, how will the energy stored in the capacitor change? V1+ C1 O It will increase. O It will decrease. O It will stay the same.A-2 µC charge moves in an electric field between two equipotential lines. It starts at the 5 V line and moves to the 10 V line. What is the change in potential energy of the charge? O -10x106 J O 5x106 J 10x106 J O -5x106 J