A certain parallel-plate capacitor is filled with a dielectric for which K = 4.67. The area of each plate is 0.0225 m², and the plates are separated by 2.38 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 172 kN/C. What is the maximum energy that can be stored in the capacitor? Number i Units

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A certain parallel-plate capacitor is filled with a dielectric for which K = 4.67. The area of each plate is 0.0225 m2, and the plates are
separated by 2.38 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 172 kN/C. What
is the maximum energy that can be stored in the capacitor?
Number
Units
Transcribed Image Text:A certain parallel-plate capacitor is filled with a dielectric for which K = 4.67. The area of each plate is 0.0225 m2, and the plates are separated by 2.38 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 172 kN/C. What is the maximum energy that can be stored in the capacitor? Number Units
Expert Solution
Step 1

Calculate the capacitance of capacitor.

C=k×ε0×Ad

Here, k is the relative permittivity, ε0 is the permittivity of free space,  A is the area of each plate and d is the distance between plates.

Put the known values and solve.

C=4.67×8.85×10-12×0.02252.38×10-3   =3.907×10-10 F

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