EXERCISE A constant electric field with magnitude 1.50 x 10³ N/C is pointing in the positive x-direction. An electron is fired from x-0.0200 m in the same direction as the electric field. The electron's speed has fallen by half when it reaches x 0.190 m, a change in potential energy of 5.04 x 10-171. The electron continues to *-0.230 m within the constant electric field. If there's a change in potential energy of -1.01 x 107 as it goes from x0.190 m tox-0.230 m, find the electron's speed (in m/s) at x -0.230 m. Hint 1.75m? Set the kinetic energy (expressed in terms of speed and mass) equat to the work done by the electric field on the particle, and solve for the speed of the particle m/s Need Help?

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M8
HEN
EXERCISE
A constant electric field with magnitude 1.50 x 10³ N/C is pointing in the positive x-direction. An electron is fired from x-0.0200 m in the same direction as the
electric field. The electron's speed has fallen by half when it reaches x 0.190 m, a change in potential energy of 5.04 x 10-17 1. The electron continues to
x=-0.230 m within the constant electric field. If there's a change in potential energy of -1.01 x 10-16) as it goes from x0.190 m tox -0.230 m, find the
electron's speed (in m/s) at x = -0.230 m.
Hint
1757
Set the kinetic energy (expressed in terms of speed and mass) equal to the work done by the electric field on the particle, and solve for the speed of the particle. m/s
Need Help?
Transcribed Image Text:HEN EXERCISE A constant electric field with magnitude 1.50 x 10³ N/C is pointing in the positive x-direction. An electron is fired from x-0.0200 m in the same direction as the electric field. The electron's speed has fallen by half when it reaches x 0.190 m, a change in potential energy of 5.04 x 10-17 1. The electron continues to x=-0.230 m within the constant electric field. If there's a change in potential energy of -1.01 x 10-16) as it goes from x0.190 m tox -0.230 m, find the electron's speed (in m/s) at x = -0.230 m. Hint 1757 Set the kinetic energy (expressed in terms of speed and mass) equal to the work done by the electric field on the particle, and solve for the speed of the particle. m/s Need Help?
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