ES → ES' v = k,[ES] ES' → E+ P v = k,[ES'] Show that the rate of formation of product has the same form as that shown in egn 17F.16, but with vmar and K, given by kk[E]o V max = k.(K+k,) KM = K,(k, +k. ) P17F.6 For many enzymes, the mechanism of action involves the formation of two intermediates: E+S→ ES v = k,[E][S] ES → E +S v = k, [ES]

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ES → ES'
v = k,[ES]
ES' → E+ P
v = k,[ES']
Show that the rate of formation of product has the same form as that shown in
egn 17F.16, but with vmar and K, given by
kk[E]o
V max =
k.(K+k,)
KM =
K,(k, +k. )
P17F.6 For many enzymes, the mechanism of action involves the formation of
two intermediates:
E+S→ ES
v = k,[E][S]
ES → E +S
v = k, [ES]
Transcribed Image Text:ES → ES' v = k,[ES] ES' → E+ P v = k,[ES'] Show that the rate of formation of product has the same form as that shown in egn 17F.16, but with vmar and K, given by kk[E]o V max = k.(K+k,) KM = K,(k, +k. ) P17F.6 For many enzymes, the mechanism of action involves the formation of two intermediates: E+S→ ES v = k,[E][S] ES → E +S v = k, [ES]
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