Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering (He) from gold-197 nuclei (197AU). The energy of the incoming helium nucleus was 7.09 x 10-13 J, and the masses of the helium and gold nuclei were 6 3.29 x 10-25 kg, respectively (note that their mass ratio is 4 to 197. Assume that the helium nucleus travels in the +x-direction before the collision.) (a) If a helium nucleus scatters to an angle of 115° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 120° He nucleus Gold nucleus 4He speed 14562052.73 x m/s 197Au velocity x m/s 1160023.058 197 Au direction -12.76 X ° counterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus?

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Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei
(*He) from gold-197 nuclei (19/Au). The energy of the incoming helium nucleus was 7.09 x 10¬13 j, and the masses of the helium and gold nuclei were 6.68 × 10¬27 kg and
3.29 x 10-25
kg, respectively (note that their mass ratio is 4 to 197. Assume that the helium nucleus travels in the +x-direction before the collision.)
(a) If a helium nucleus scatters to an angle of 115° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity
(magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus.
120°
He nucleus
Gold nucleus
4He speed
X m/s
14562052.73
197 Au velocity
X m/s
1160023.058
197 Au direction
-12.76
counterclockwise from the +x-axis
(b) What is the final kinetic energy (in J) of the helium nucleus?
Transcribed Image Text:Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (*He) from gold-197 nuclei (19/Au). The energy of the incoming helium nucleus was 7.09 x 10¬13 j, and the masses of the helium and gold nuclei were 6.68 × 10¬27 kg and 3.29 x 10-25 kg, respectively (note that their mass ratio is 4 to 197. Assume that the helium nucleus travels in the +x-direction before the collision.) (a) If a helium nucleus scatters to an angle of 115° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 120° He nucleus Gold nucleus 4He speed X m/s 14562052.73 197 Au velocity X m/s 1160023.058 197 Au direction -12.76 counterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus?
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