Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (He) from gold-197 (197 Au). See the figure below. The energy of the incoming helium nucleus was 8.90 x 10-13), and the masses of the helium and gold nuclei were 6.68 x 10-27 and 3.29 x 10-25 kg, respectively (note that their mass ratio is 4 to 197). If a helium nucleus scatters to an angle of 120° during an elastic collision with a gold nucleus, calculate the helium nucleus's final speed. m/s Calculate the final velocity (magnitude and direction) of the gold nucleus. (Assume the positive x direction is the direction in which the helium nucleus is initially traveling, and that it scatters 120° clockwise from the +x-axis.) magnitude m/s direction (counterclockwise from the +x-axis) + MA → Before collision After collision

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Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (4He) from gold-197 (197 Au). See the figure below. The energy of the incoming helium nucleus
was 8.90 × 10-13 J, and the masses of the helium and gold nuclei were 6.68 × 10-27 and 3.29 × 10-25 kg, respectively (note that their mass ratio is 4 to 197). If a helium nucleus scatters to an angle of 120° during an elastic collision with a gold nucleus, calculate the
helium nucleus's final speed.
m/s
Calculate the final velocity (magnitude and direction) of the gold nucleus. (Assume the positive x direction is the direction in which the helium nucleus is initially traveling, and that it scatters 120° clockwise from the +x-axis.)
magnitude
m/s
direction
° (counterclockwise from the +x-axis)
4He
Additional Materials
Reading
y
197 Au
Before collision
He
1/
197 Au
0=120°
After collision
Transcribed Image Text:Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (4He) from gold-197 (197 Au). See the figure below. The energy of the incoming helium nucleus was 8.90 × 10-13 J, and the masses of the helium and gold nuclei were 6.68 × 10-27 and 3.29 × 10-25 kg, respectively (note that their mass ratio is 4 to 197). If a helium nucleus scatters to an angle of 120° during an elastic collision with a gold nucleus, calculate the helium nucleus's final speed. m/s Calculate the final velocity (magnitude and direction) of the gold nucleus. (Assume the positive x direction is the direction in which the helium nucleus is initially traveling, and that it scatters 120° clockwise from the +x-axis.) magnitude m/s direction ° (counterclockwise from the +x-axis) 4He Additional Materials Reading y 197 Au Before collision He 1/ 197 Au 0=120° After collision
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