Equimolar amounts of H2(g) and CO(g) are mixed in a container at 25 °C. The reaction H2(g) + CO(g) ? HCHO(g) takes place. What is the mol fraction of formaldehyde, HCHO, at equilibrium when the total pressure is 10 atm? Assume that you can treat the system at equilibrium as an ideal gas mixture. AG°(CO,g) = -137.17 kJ / mol AG°(HCHO,g) = -102.53 kJ / mol
Equimolar amounts of H2(g) and CO(g) are mixed in a container at 25 °C. The reaction H2(g) + CO(g) ? HCHO(g) takes place. What is the mol fraction of formaldehyde, HCHO, at equilibrium when the total pressure is 10 atm? Assume that you can treat the system at equilibrium as an ideal gas mixture. AG°(CO,g) = -137.17 kJ / mol AG°(HCHO,g) = -102.53 kJ / mol
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Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.19QP: During an experiment with the Haber process, a researcher put 1 mol N2 and 1 mol H2 into a reaction...
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![Equimolar amounts of H₂(g) and CO(g) are mixed in a container at 25 °C. The reaction
\[ \text{H}_2(g) + \text{CO}(g) \rightleftharpoons \text{HCHO}(g) \]
takes place. What is the mol fraction of formaldehyde, HCHO, at equilibrium when the total pressure is 10 atm? Assume that you can treat the system at equilibrium as an ideal gas mixture.
\[\Delta G^\circ(\text{CO},g) = -137.17 \, \text{kJ/mol} \]
\[\Delta G^\circ(\text{HCHO},g) = -102.53 \, \text{kJ/mol} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35899798-0d4b-4973-bce0-69caa4d3c203%2Fb950a2e6-f596-4e4d-b53b-a844bf6d6e68%2F19tne3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Equimolar amounts of H₂(g) and CO(g) are mixed in a container at 25 °C. The reaction
\[ \text{H}_2(g) + \text{CO}(g) \rightleftharpoons \text{HCHO}(g) \]
takes place. What is the mol fraction of formaldehyde, HCHO, at equilibrium when the total pressure is 10 atm? Assume that you can treat the system at equilibrium as an ideal gas mixture.
\[\Delta G^\circ(\text{CO},g) = -137.17 \, \text{kJ/mol} \]
\[\Delta G^\circ(\text{HCHO},g) = -102.53 \, \text{kJ/mol} \]
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