enote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Round all answers to two decimal places.) (e) P(z > z*) = 0.0098 z* =
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Let z denote a variable that has a standard
(e) P(z > z*) = 0.0098
z* =
The probability of standard normal distribution can be obtained from standard normal table or any software
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- -3 -2 -1 0 1 2 3 Please show your answer to 2 decimal places. About % of the area under the curve of the standard normal distribution (u = 0 and o = 1) is outside the interval Z = (-1.02,1.02) (or beyond 1.02 standard deviations of the mean).Short Answer 1. Use the normal approximation to find u and o in a binomial distribution with n = 1000 and p = 0.5.Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Round your answers to two decimal places.) (a) P(z < z*) = 0.0244 z* = (b) P(z < z*) = 0.0101 z* = (c) P(z < z*) = 0.0504 z* = (d) P(z > z*) = 0.0199 z* = (e) P(z > z*) = 0.0101 z* = (f) P(z > z* or z < −z*) = 0.1969 z* =
- Current Attempt in Progress Let x have a normal distribution with a mean of 57.7 and a standard deviation of 4.95. The z value for x = 43.38, rounded to two decimal places, is: i2-3 -2 -1 0 1 2 3 0 and For a standard normal distribution (u = 1), find c given P(Z > c) = 0.079, please show your answer to 2 decimal places. || C =
- Let the test statistic T have a t distribution when Ho is true. Give the P-value for each of the following situations. (Round your answers to three decimal places.) USE SALT (a) Ha: μ> Mo, df = 15, t = 2.864 P-value = 0.983 X (b) Ha: μ< μo, n = 24, t = 2.234 P-value = (c) H₂:μμ₁, n = 31, t = -1.691 or t = 1.691 P-value =Consider the normal distribution represented by the normal curve in the figure to the right. (Assume the two labeled values are equidistant from the mean.) Complete parts (a) and (b) below. 95% of the data 73.2 cm 96.8 cm (a) Find the mean μ and standard deviation σ of the distribution. με cm (Simplify your answer.) σ = cm (Simplify your answer.) (b) Find the first quartile Q1 and the third quartile Q3 of the distribution. ༠ ༤ cm (Round to the nearest tenth as needed.) Q3≈ cm (Round to the nearest tenth as needed.)Determine to 3 decimal places the value of x² for 25 degrees of freedom and an area of 0.990 in the left tail of the chi-square distribution curve. x² = i
- Let x = red blood cell (RBC) count in millions per cubic millimeter of whole blood. For healthy females, x has an approximately normal distribution with mean ? = 3.4 and standard deviation ? = 0.5. Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.)____ < zConvert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.)z < ____ Convert the x interval, 4.0 < x < 5.5, to a z interval. (Round your answers to two decimal places.)____ < z < ___Convert the z interval, z < −1.44, to an x interval. (Round your answer to one decimal place.)x < ____ Convert the z interval, 1.28 < z, to an x interval. (Round your answer to one decimal place.)____ < xConvert the z interval, −2.25 < z < −1.00, to an x interval. (Round your answers to one decimal place.)____ < x < ___If a female had an RBC count of 5.9 or higher, would that be considered unusually high? Explain using z values.…Let x = red blood cell (RBC) count in millions per cubic millimeter of whole blood. For healthy females, x has an approximately normal distribution with mean u - 5.3 and standard deviation a - 0.7. The Standard Normal Distribution u = 0, o = 1) -1 68% of area 95% of area 99.7% of area (a) Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.) (b) Convert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.) z< (c) Convert the x interval, 4.0 < x< 5.5, to a z interval. (Round your answers to two decimal places.)
