Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean u = 29.6 kilograms and standard deviation o = 5.0 kilograms. Let x be the weight of a fawn in kilograms.The Standard Normal Distributionu = 0, o = 1)-2368% of area95% of area99.7% of areaFor parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.)(a) x< 301x(b) 19 < x (Fill in the blank. A blank is represented by )(c) 32 < x < 35 (Fill in the blanks. A blank is represented by There are two answer blanks.)first blanksecond blankFor parts (d), (e), and (f), convert the z intervals to x intervals. (For each answer, enter a number. Round your answers to one decimal place.)(d) -2.17 < z (Fill in the blank. A blank is represented by )(e)z< 1.28(f)-1.99 < z< 1.44 (Fill in the blanks. A blank is represented byThere are two answer blanks.)first blanksecond blank(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.O Yes. This weight is 3.12 standard deviations below the mean; 14 kg is an unusually lovw weight for a fawn.O Yes. This wreight is 1.56 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.O No. This weight is 3.12 standard deviations below the mean; 14 kg is a normal weight for a fawn.O No. This weight is 3.12 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.O No. This weight is 1.56 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

Hi, we are supposed to answer three subparts at a time. Since you have not mentioned which subpart…

body welgh distric The Standard Normal Distribution u- 0, o- 1) -2 -1 68% of area 95% of area 99.7% of area For parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.) (а) х< 30 1x (b) 19 < x (Fill in the blank. A blank represented by ) (c) 32

body welgh distric The Standard Normal Distribution u- 0, o- 1) -2 -1 68% of area 95% of area 99.7% of area For parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.) (а) х< 30 1x (b) 19 < x (Fill in the blank. A blank represented by ) (c) 32

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!

Question

100%

Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean u = 29.6 kilograms and standard deviation o = 5.0 kilograms. Let x be the weight of a fawn in kilograms.
The Standard Normal Distribution
u = 0, o = 1)
-2
3
68% of area
95% of area
99.7% of area
For parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.)
(a) x< 30
1x
(b) 19 < x (Fill in the blank. A blank is represented by )
(c) 32 < x < 35 (Fill in the blanks. A blank is represented by There are two answer blanks.)
first blank
second blank
For parts (d), (e), and (f), convert the z intervals to x intervals. (For each answer, enter a number. Round your answers to one decimal place.)
(d) -2.17 < z (Fill in the blank. A blank is represented by )
(e)
z< 1.28
(f)
-1.99 < z< 1.44 (Fill in the blanks. A blank is represented by
There are two answer blanks.)
first blank
second blank
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
O Yes. This weight is 3.12 standard deviations below the mean; 14 kg is an unusually lovw weight for a fawn.
O Yes. This wreight is 1.56 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.
O No. This weight is 3.12 standard deviations below the mean; 14 kg is a normal weight for a fawn.
O No. This weight is 3.12 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.
O No. This weight is 1.56 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

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