-3 -2 -1 0 1 2 3 Please show your answer to 2 decimal places. About % of the area under the curve of the standard normal distribution (µ = 0 and o = 1) is butside the interval Z = (-1.43,1.43) (or beyond 1.43 standard deviations of the mean).
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- Hayley has 120 apple trees of a certain variety in her orchard. She estimates the population of apples has a mean of 9 seeds per apple with a standard deviation of 2 seeds. The distribution in the number of seeds per apple has a shape that is approximately normal. The table gives the standard normal distribution. What percent of Hayley's apples have between 5 and 11 seeds? Enter your answer in the box rounded to the tenths place.uppose the lengths of human pregnancies are normally distributed with μ=266 days and σ=16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with μ=266 days and σ=16 days. The area to the left of X=235 is 0.0263. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last more than nothing days is nothing. B. The proportion of human pregnancies that last less than days is X 266 235 A normal curve has a horizontal axis labeled "X" and two horizontal coordinates, 235 and 266. The curve's peak is near the top of the graph at horizontal coordinate 266. Two vertical line segments run from the horizontal axis to the curve at 235 and 266. The area under the curve to…I got it wrong, please help with explanation step by step.
- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.t Over a period of months, an adult male patient has taken seven blood tests for uric acid. The mean concentration was x = 5.29 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with o = 1.95 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) On is large O o is known O o is unknown O normal distribution of uric acid O uniform distribution of uric acid (c) Interpret your results in the context of this problem. O we are 95% confident that the true uric acid level for this patient falls within this interval. O we are 5% confident that…A normal distribution with a mean of 2mm and a standard deviation of 0.05mm a randomly generated number of 0.71 , need to calculate the standardised Z value, from my notes Z = (actual value - mean)/standard deviation. do i take the randomly generated number of 0.81 as the actual value ?Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2= -0.81 z=1.21 The area of the shaded region is (Round to four decimal places as needed.)
- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.t Over a period of months, an adult male patient has taken nine blood tests for uric acid. The mean concentration was x = 5.41 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with o = 1.75 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid On is large O o is unknown O uniform distribution of uric acid O o is known (c) Interpret your results in the context of this problem. The probability that this interval contains the true average uric acid level for this patient is 0.95. The probability that this…I need help with the last 3 please.Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of th - × The area of the shaded r Standard Normal Table (Page 1) NEGATIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 -3.50 and lower .0001 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0003 0004 .0003 .0004 .0003 .0004 .0002 .0003 -3.2 .0007 .0007 .0006 0006 .0006 .0006 .0006 .0005 .0005 .0005 -3.1 .0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 0007 .0007 -3.0 .0013 .0013 0013 .0012 0012 .0011 .0011 .0011 0010 0010 -2.9 .0019 0018 0018 .0017 .0016 .0016 .0015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 .0019 -2.7 .0035 .0034 .0033 .0032 .0031 .0030 .0029 .0028 .0027 .0026 -2.6 .0047 .0045 0044 .0043 .0041 .0040 .0039 .0038 .0037 .0036 -2.5 .0062…
