The lifetime X of a widget has a Weibull distribution with parameters a = 2 and B = 5. The mean widget lifetime is E[X] = 4.43. The standard deviation of the lifetime is StDev(X) = 2.316. What is the probability the widget lasts between 2.6 and 5.2? P( 2.6 < X < 5.2 ) = Express your answer as a proportion rounded to 4 decimal places.
The lifetime X of a widget has a Weibull distribution with parameters a = 2 and B = 5. The mean widget lifetime is E[X] = 4.43. The standard deviation of the lifetime is StDev(X) = 2.316. What is the probability the widget lasts between 2.6 and 5.2? P( 2.6 < X < 5.2 ) = Express your answer as a proportion rounded to 4 decimal places.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![The lifetime X of a widget has a Weibull distribution with parameters a = 2 and B = 5.
The mean widget lifetime is E[X] = 4.43. The standard deviation of the lifetime is StDev(X) = 2.316.
What is the probability the widget lasts between 2.6 and 5.2? P( 2.6 < X < 5.2 ) =
Express your answer as a proportion rounded to 4 decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe1bea67f-a5b0-4470-ab98-e35bade0dec5%2Fa388ee91-a52e-4243-a2cd-0e1f6939f92e%2Fe8hj7vl_processed.png&w=3840&q=75)
Transcribed Image Text:The lifetime X of a widget has a Weibull distribution with parameters a = 2 and B = 5.
The mean widget lifetime is E[X] = 4.43. The standard deviation of the lifetime is StDev(X) = 2.316.
What is the probability the widget lasts between 2.6 and 5.2? P( 2.6 < X < 5.2 ) =
Express your answer as a proportion rounded to 4 decimal places.
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