The lifetime X of a widget has a Weibull distribution with parameters a =2 and B = 5.The mean widget lifetime is E[X] = 4.43. The standard deviation of the lifetime is StDev(X) = 2.316.Suppose we order a package of 50 widgets. Let To represent the total lifetime of all the widgets. On average, whatis the total lifetime of all 50 widgets? E(To) =Round your answer to 1 decimal place.

Given.... The lifetime X of a widget has a Weibull distribution with parameters a = 2 and 3 = 5. The…

Answered: The lifetime X of a widget has a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Growth spurt: it is generally known that boys grow at an unusually fast rate between the ages of about 12 and 14. Following are heights, in inches of 10 boys, measured at age 12 and again at age 14. Can you conclude that the mean increase in height differs from 5 inches? Let u1 represent the mean height at age 14 and ud= u1-u2. Use the a=0.01 level and the p-value method with the TI-84 calculator. Age12 58.1 63.3 61.2 64.5 55.9 60.4 57.8 68.3 63 64.4 Age14 63.3 69.6 66.4 69.2 62 65.7 62.8 73.6 67.7 69.2
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 66.4 inches tall. (to 2 decimal places) Submit Question logi esc *3 W E R T S D F. D. %24
Approximate the population mean and standard deviation of age for females.
Suppose that replacement times for washing machines are normally distributed with a mean of μ=8.7 years and a standard deviation of σ=1.6 years. Find P25 the replacement time that separates the bottom 25% from the top 75%
Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV1. Assume the mean FEV1 for 10 -year-old boys is 2.1 liters and that the population standard deviation is =σ0.4 . A random sample of 35 10 -year-old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV1 of 1.98 liters. Can you conclude that the mean FEV1 in the high-pollution community differs from 2.1 liters? Use the =α0.10 level of significance and the P -value method with the TI-84 calculator. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 State the appropriate null and alternate hypotheses. :H0 :H1 This hypothesis test is a ▼(Choose one) test.
The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 14 days. A distribution of values is normal with a mean of 267 and a standard deviation of 14. What percentage of pregnancies last fewer than 274 days? P(X < 274 days) Let XX represent the full height of certain species of tree. Assume that XX is normally distributed with a mean of 82.1 feet and a standard deviation of 47.9 feet.Find the probability that the full height of a randomly selected tree is greater than 154 feet. P(X>154)
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The average daily high temperature in degrees Celsius (C) during the month of July was recorded for the 51 largest cities in the United States. Summary measures are shown below. Mean 30.84 Standard Deviation 3.78 Median IQR 31 5 Range 22 Which of the following represents the median and interquartile range (IQR) of these average daily high temperatures in degrees Fahrenheit (F), where F = (3) C + 32? (A) Median = 52.8°F, IQR = 9°F (B) Median = 52.8°F, IQR = 41°F (C) Median 87.8°F, IQR = 5°F (D) Median = 87.8°F, IQR = 9°F (E) Median 87.8°F, IQR = 41°F
Find the mean, variance, and standard deviation for f(x). Round the standard deviation to three decimal places. 192 if x24 f(x) = . х 0 otherwise O A. 6; 12; 3.464 O B. 48; 2,256; 47.497 O C. 6; 48; 6.928 O D. 96; 9,024; 94.995 Click to select your answer.
Q.8
Suppose that the recovery time from the infection with a certain virus is normally distributed with a mean of 6.5 days and a standard deviation of 1.5 days. Answer each question. Draw a graph illustrating the recovery time. Make sure to indicate 3 standard deviations from the mean. P(X>7.3)=? P(X <4.7)=? P(5.1<X<7.7)=? John's recovery time is lasting more than 9.2 days. Is it unusual (and should he be concerned yet)? What is the middle 90% recovery time? What is the 80%tile recovery time?
Which of the following can NEVER be less than zero. Select all that apply. Group of answer choices probability correlation coefficient interquartile range z-score standard deviation

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