Let x = red blood cell (RBC) count in millions per cubic millimeter of whole blood. For healthy females, x has an approximately normal distribution with mean ? = 3.4 and standard deviation ? = 0.5.    Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.) ____ < z Convert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.) z < ____  Convert the x interval, 4.0 < x < 5.5, to a z interval. (Round your answers to two decimal places.) ____ < z < ___

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 15E: Describe the standard normal distribution. What are its characteristics?
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Let x = red blood cell (RBC) count in millions per cubic millimeter of whole blood. For healthy females, x has an approximately normal distribution with mean ? = 3.4 and standard deviation ? = 0.5.

 
 Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.)
____ < z

Convert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.)
z < ____
 Convert the x interval, 4.0 < x < 5.5, to a z interval. (Round your answers to two decimal places.)
____ < z < ___

Convert the z interval, z < −1.44, to an x interval. (Round your answer to one decimal place.)
x < ____
 
 Convert the z interval, 1.28 < z, to an x interval. (Round your answer to one decimal place.)
____ < x

Convert the z interval, −2.25 < z < −1.00, to an x interval. (Round your answers to one decimal place.)
____ < x < ___

If a female had an RBC count of 5.9 or higher, would that be considered unusually high? Explain using z values.
Yes. A z score of 5.00 implies that this RBC is unusually high.
No. A z score of −5.00 implies that this RBC is unusually low.    
No. A z score of 5.00 implies that this RBC is normal.
 
The Standard Normal Distribution
(u = 0, o = 1)
%3D
3
-2
3
68% of area
95% of area
99.7% of area
Transcribed Image Text:The Standard Normal Distribution (u = 0, o = 1) %3D 3 -2 3 68% of area 95% of area 99.7% of area
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