Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributedwith a mean of 14.3 in. and a standard deviation of 0.8 in. Find Pao. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%.The hip breadth for men that separates the smallest 90% from the largest 10% is Pan =|2 in.(Round to one decimal place as needed.)

Given : Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard…

Answered: Engineers want to design seats in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An engineer working for a manufacturer of electronic components takes a large number of measurements of a particular dimension of components from the production line. She finds that the distribution of dimensions is normal, with a mean of 2.340 cm and a standard deviation of 0.056 cm. a.) What percentage of measurements will be greater than 2.45 cm.? b.) What percentage of dimensions will be between 2.25 cm. and 2.45 cm.? c.) What value of the dimension will not be exceeded by 98% of the components?
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 13.6 in. and a standard deviation of 1.2 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.7 in. and a standard deviation of 0.8 in. Find Pas That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is P95 =in. (Round to one decimal place as needed.)
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard deviation of 0.9 in. Find Pas. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is Pas = in. (Round to one decimal place as needed.)
Most people think that the "normal" adult body temperature is 98.6°F. In a more recent study, researchers reported that a more accurate figure may be 98.1°F. Furthermore, the standard deviation appeared to be around 0.7°F. Assume that a Normal model is appropriate. b) What fraction of people would be expected to have body temperatures above 98.6°F?
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much to0 expensive.) Men have hip breadths that are normally distributed with a mean of 14.7 in. and a standard deviation of 0.9 in. Find Por. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is Pas = (Round to one decimal place as needed.) in.
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95%of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.1in. and a standard deviation of 1.2in. Find P95 That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is P95=enter your response herein. (Round to one decimal place as needed.)
(Same question just could not fit all into one photo)
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.9 in. and a standard deviation of 1.1 in. Find Pg9. That is, find the hip breadth for men that separates the smallest 99% from the largest 1%. The hip breadth for men that separates the smallest 99% from the largest 1% is Pgg in. %3D (Round to one decimal place as needed.)
Companies who design furniture for elementary school classrooms produce a variety of sizes for children of different ages. Suppose the heights of kindergarten children are normally distributed with a mean of 97 cm and a standard deviation of 4.9 cm. What proportion of kindergarten children should the company expect to be less than 91 cm tall?

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