Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard deviation of 0.9 in. Find P90- That is, the hip breadth for men that separates the smallest 90% from the largest 10%. *** - The hip breadth for men that separates the smallest 90% from the largest 10% is P90 = in. (Round to one decimal place as needed.)

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**Designing Aircraft Seats for Optimal Fit**

Engineers aim to design seats in commercial aircraft that are sufficiently wide to fit 90% of all males. Accommodating 100% of males would require excessively wide and expensive seats. Men's hip breadths follow a normal distribution with a mean of 14.3 inches and a standard deviation of 0.9 inches. 

**Objective**: Calculate \( P_{90} \), the hip breadth measurement that separates the smallest 90% from the largest 10%.

**Task**: Determine the hip breadth for men that distinguishes the smallest 90% from the largest 10%.

\[ \text{The hip breadth for men that separates the smallest 90% from the largest 10% is } P_{90} = \_ \text{ inches.} \] 

*Round to one decimal place as needed.*
Transcribed Image Text:**Designing Aircraft Seats for Optimal Fit** Engineers aim to design seats in commercial aircraft that are sufficiently wide to fit 90% of all males. Accommodating 100% of males would require excessively wide and expensive seats. Men's hip breadths follow a normal distribution with a mean of 14.3 inches and a standard deviation of 0.9 inches. **Objective**: Calculate \( P_{90} \), the hip breadth measurement that separates the smallest 90% from the largest 10%. **Task**: Determine the hip breadth for men that distinguishes the smallest 90% from the largest 10%. \[ \text{The hip breadth for men that separates the smallest 90% from the largest 10% is } P_{90} = \_ \text{ inches.} \] *Round to one decimal place as needed.*
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