Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults woul expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)

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Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too
expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That is, find the hip width for adults that separates the
smallest 99% from the largest 1%.
What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults?
in. (Round to one decimal place as needed.)
Transcribed Image Text:Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)
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