Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.8 in. and a standard deviation of 0.9 in. Find Pg5. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is P95 =D in. (Round to one decimal place as needed.)

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**Designing Aircraft Seats for Optimal Fit**

Engineers are tasked with designing seats in commercial aircraft that are wide enough to accommodate 95% of all males. Accommodating 100% of males would necessitate very wide seats, leading to impractical cost implications. Men's hip breadths are normally distributed with a mean of 14.8 inches and a standard deviation of 0.9 inches. The goal is to find \( P_{95} \), which represents the hip breadth that separates the smallest 95% from the largest 5%.

To find this, we need to calculate the hip breadth for men that demarcates the smallest 95% from the largest 5%, represented as \( P_{95} = \) [input value] inches. This value should be rounded to one decimal place as needed.
Transcribed Image Text:**Designing Aircraft Seats for Optimal Fit** Engineers are tasked with designing seats in commercial aircraft that are wide enough to accommodate 95% of all males. Accommodating 100% of males would necessitate very wide seats, leading to impractical cost implications. Men's hip breadths are normally distributed with a mean of 14.8 inches and a standard deviation of 0.9 inches. The goal is to find \( P_{95} \), which represents the hip breadth that separates the smallest 95% from the largest 5%. To find this, we need to calculate the hip breadth for men that demarcates the smallest 95% from the largest 5%, represented as \( P_{95} = \) [input value] inches. This value should be rounded to one decimal place as needed.
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