Electromagnetic radiation with a wavelength of 425 nm appears as violet light to the human eye. The energy of one photon of this light is J. 8.45 × 10-32 O 4.68 x 10-19 2.14 x 1018 4.68 x 10-28 O 8.45 × 10-23

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Chapter1: Chemical Foundations
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### Understanding Photon Energy in Electromagnetic Radiation

Electromagnetic radiation with a wavelength of 425 nm appears as violet light to the human eye. The energy of one photon of this light is _______ J.

#### Multiple Choice Answers:
- \( \mathbf{A. \; 8.45 \times 10^{-32} \; J} \)
- \( \mathbf{B. \; 4.68 \times 10^{-19} \; J} \)
- \( \mathbf{C. \; 2.14 \times 10^{18} \; J} \)
- \( \mathbf{D. \; 4.68 \times 10^{-28} \; J} \)
- \( \mathbf{E. \; 8.45 \times 10^{-23} \; J} \)

#### Explanation:

This question deals with the concept of photon energy in the context of electromagnetic radiation. Light of different wavelengths corresponds to different energies, and this specific wavelength (425 nm) falls into the visible spectrum, appearing as violet light.

To calculate the energy \(E\) of a photon, you can use the formula:
\[ E = \frac{hc}{\lambda} \]

Where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \; \text{J} \cdot \text{s} \))
- \( c \) is the speed of light (\( 3.00 \times 10^8 \; \text{m/s} \))
- \( \lambda \) is the wavelength (\( 425 \times 10^{-9} \; \text{m} \))

Substituting these values in, you will find the correct energy value.

The correct answer has been pre-selected as \( \mathbf{D. \; 4.68 \times 10^{-28} \; J} \), signified by the blue circle.

This example highlights the essential principle that visible light spans a range of energies, each correlating to a specific wavelength within the electromagnetic spectrum. Understanding this relationship is crucial in fields ranging from physics to optical engineering.
Transcribed Image Text:### Understanding Photon Energy in Electromagnetic Radiation Electromagnetic radiation with a wavelength of 425 nm appears as violet light to the human eye. The energy of one photon of this light is _______ J. #### Multiple Choice Answers: - \( \mathbf{A. \; 8.45 \times 10^{-32} \; J} \) - \( \mathbf{B. \; 4.68 \times 10^{-19} \; J} \) - \( \mathbf{C. \; 2.14 \times 10^{18} \; J} \) - \( \mathbf{D. \; 4.68 \times 10^{-28} \; J} \) - \( \mathbf{E. \; 8.45 \times 10^{-23} \; J} \) #### Explanation: This question deals with the concept of photon energy in the context of electromagnetic radiation. Light of different wavelengths corresponds to different energies, and this specific wavelength (425 nm) falls into the visible spectrum, appearing as violet light. To calculate the energy \(E\) of a photon, you can use the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \; \text{J} \cdot \text{s} \)) - \( c \) is the speed of light (\( 3.00 \times 10^8 \; \text{m/s} \)) - \( \lambda \) is the wavelength (\( 425 \times 10^{-9} \; \text{m} \)) Substituting these values in, you will find the correct energy value. The correct answer has been pre-selected as \( \mathbf{D. \; 4.68 \times 10^{-28} \; J} \), signified by the blue circle. This example highlights the essential principle that visible light spans a range of energies, each correlating to a specific wavelength within the electromagnetic spectrum. Understanding this relationship is crucial in fields ranging from physics to optical engineering.
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