Canvas Question 52 HO A student attempt to execute the reaction below between H3CCN and KOH. ECT H₂0 pka = 15.7

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### Question 52

A student attempts to execute the reaction below between H₃CCN and KOH.

\[
\ce{H3CC–H + HO^- -> H3CC–C^- + H2O}
\]

- pKa (H₃CC–H) = 25
- pKa (H₂O) = 15.7

**Is KOH a sufficiently strong base for this process?**

1. Yes. \( K_c = 2.00 \times 10^{9} \)
2. Yes. \( K_c = 5.0 \times 10^{10} \)
3. No. \( K_c = 2.00 \times 10^{-41} \)
4. No. \( K_c = 5.0 \times 10^{-10} \)

(Note: \( K_c \) represents the equilibrium constant for the reaction.)

For a clear visual representation, this reaction is depicted with the triple bond and hydrogen on \(\ce{H3CC–H}\), transitioning to a triple bond and negative ion on \(\ce{H3CC–C^-}\) in the presence of hydroxide ion (\(\ce{HO^-}\)) and water (\(\ce{H2O}\)) forming as a byproduct. This is a typical acid-base reaction where the strength of the base (KOH) is analyzed by comparing pKa values and calculating \( K_c \).
Transcribed Image Text:### Question 52 A student attempts to execute the reaction below between H₃CCN and KOH. \[ \ce{H3CC–H + HO^- -> H3CC–C^- + H2O} \] - pKa (H₃CC–H) = 25 - pKa (H₂O) = 15.7 **Is KOH a sufficiently strong base for this process?** 1. Yes. \( K_c = 2.00 \times 10^{9} \) 2. Yes. \( K_c = 5.0 \times 10^{10} \) 3. No. \( K_c = 2.00 \times 10^{-41} \) 4. No. \( K_c = 5.0 \times 10^{-10} \) (Note: \( K_c \) represents the equilibrium constant for the reaction.) For a clear visual representation, this reaction is depicted with the triple bond and hydrogen on \(\ce{H3CC–H}\), transitioning to a triple bond and negative ion on \(\ce{H3CC–C^-}\) in the presence of hydroxide ion (\(\ce{HO^-}\)) and water (\(\ce{H2O}\)) forming as a byproduct. This is a typical acid-base reaction where the strength of the base (KOH) is analyzed by comparing pKa values and calculating \( K_c \).
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