Question 42 In which electron-orbital diagram is Hund's Rule violated? I [Ar II. [Ar) III. [Ar] IV. [Ar] ↑↓ 4s O IV. ◯WII. ◯l. ↑↑ 4s ◯ll. 4s ↑↓ 4s FF1 3d 소소소 3d ↑ 11 ↑↑↑↑↑ 3d = 一

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**Electron-Orbital Diagram Question**

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### Question 42

**In which electron-orbital diagram is Hund's Rule violated?**

Diagram options:

- **I.**  

  \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow\downarrow \quad \uparrow \quad \uparrow \quad \uparrow \quad \quad \quad 3d \]
  
- **II.**  

  \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow \quad \uparrow \quad \uparrow \quad \uparrow \quad \uparrow \quad 3d \]
  
- **III.**  

  \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow \quad \uparrow \quad \uparrow \quad \quad \quad \quad \quad \quad 3d \]
  
- **IV.**

  \[ \text{[Ar]} \quad \uparrow \quad \downarrow \quad 4s \quad \uparrow\downarrow \quad \uparrow \quad \uparrow \quad \uarrow \quad 3d \]

Answer choices:

- ( ) IV.
- ( ) III.
- ( ) I.
- ( ) II.

### Explanation

To determine which electron-orbital diagram violates Hund's Rule, we need to understand Hund's Rule:
**Hund's Rule** states that electrons must occupy every orbital singly before any orbital is doubly occupied. Additionally, all electrons in singly occupied orbitals must have the same spin.

Diagram-by-diagram analysis:
- **Diagram I** violates Hund's Rule because the 3d orbitals are doubly occupied before all orbitals are singly occupied.
- **Diagram II** does not violate Hund's Rule as all orbitals in 3d are singly occupied with the same spin.
- **Diagram III** does not violate Hund's Rule because it adheres to the principle of singly occupying each 3d orbital before any pairing occurs.
- **Diagram IV** also violates Hund's Rule because the 4s orbital should be doubly occupied with the correct spin alignment.

After this analysis, it's clear that **Diagram I** is the one in which Hund's Rule is violated.
Transcribed Image Text:**Electron-Orbital Diagram Question** --- ### Question 42 **In which electron-orbital diagram is Hund's Rule violated?** Diagram options: - **I.** \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow\downarrow \quad \uparrow \quad \uparrow \quad \uparrow \quad \quad \quad 3d \] - **II.** \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow \quad \uparrow \quad \uparrow \quad \uparrow \quad \uparrow \quad 3d \] - **III.** \[ \text{[Ar]} \quad \uparrow\downarrow \quad 4s \quad \uparrow \quad \uparrow \quad \uparrow \quad \quad \quad \quad \quad \quad 3d \] - **IV.** \[ \text{[Ar]} \quad \uparrow \quad \downarrow \quad 4s \quad \uparrow\downarrow \quad \uparrow \quad \uparrow \quad \uarrow \quad 3d \] Answer choices: - ( ) IV. - ( ) III. - ( ) I. - ( ) II. ### Explanation To determine which electron-orbital diagram violates Hund's Rule, we need to understand Hund's Rule: **Hund's Rule** states that electrons must occupy every orbital singly before any orbital is doubly occupied. Additionally, all electrons in singly occupied orbitals must have the same spin. Diagram-by-diagram analysis: - **Diagram I** violates Hund's Rule because the 3d orbitals are doubly occupied before all orbitals are singly occupied. - **Diagram II** does not violate Hund's Rule as all orbitals in 3d are singly occupied with the same spin. - **Diagram III** does not violate Hund's Rule because it adheres to the principle of singly occupying each 3d orbital before any pairing occurs. - **Diagram IV** also violates Hund's Rule because the 4s orbital should be doubly occupied with the correct spin alignment. After this analysis, it's clear that **Diagram I** is the one in which Hund's Rule is violated.
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