Give the ground state electron configuration for the ion of Cs forms. O [kr]5s²4d105p6 O [Kr]5s24d105p66s¹ O [kr]5s25p6 O [Kr]5s24d105p66s²6p² O [Kr]5s24d105p66s²
Formal Charges
Formal charges have an important role in organic chemistry since this concept helps us to know whether an atom in a molecule is neutral/bears a positive or negative charge. Even if some molecules are neutral, the atoms within that molecule need not be neutral atoms.
Polarity Of Water
In simple chemical terms, polarity refers to the separation of charges in a chemical species leading into formation of two polar ends which are positively charged end and negatively charged end. Polarity in any molecule occurs due to the differences in the electronegativities of the bonded atoms. Water, as we all know has two hydrogen atoms bonded to an oxygen atom. As oxygen is more electronegative than hydrogen thus, there exists polarity in the bonds which is why water is known as a polar solvent.
Valence Bond Theory Vbt
Valence bond theory (VBT) in simple terms explains how individual atomic orbitals with an unpaired electron each, come close to each other and overlap to form a molecular orbital giving a covalent bond. It gives a quantum mechanical approach to the formation of covalent bonds with the help of wavefunctions using attractive and repulsive energies when two atoms are brought from infinity to their internuclear distance.
![**Ground State Electron Configuration of Cs Ion**
Understanding the electron configuration of ions is essential in mastering the fundamental concepts of chemistry. The following multiple-choice question is designed to test your knowledge of this topic.
**Question:**
Give the ground state electron configuration for the ion of Cs forms.
**Options:**
1. \( [Kr] 5s^2 4d^{10} 5p^6 \)
2. \( [Kr] 5s^2 4d^{10} 5p^6 6s^1 \)
3. \( [Kr] 5s^2 5p^6 \)
4. \( [Kr] 5s^2 4d^{10} 5p^6 6s^2 6p^2 \)
5. \( [Kr] 5s^2 4d^{10} 5p^6 6s^2 \)
**Explanation:**
The goal is to determine the correct electron configuration for the cesium ion (Cs). Remember that when forming an ion, cesium (Cs) typically loses one electron, forming a \( Cs^+ \) ion.
The starting neutral configuration for Cs is:
\[ [Xe] 6s^1 \]
When Cs loses one electron to form \( Cs^+ \),
the resulting electron configuration would be:
\[ [Xe] \]
However, this representation might be simplified using the configuration of the preceding noble gas, Krypton (Kr), to validate the loss process.
Choose the correct option to reflect this understanding.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30d9daac-bb71-46b3-af88-60b407cbaed8%2F9d63ff2d-8c75-4bb2-9c94-29f0bfd56074%2Ftkh3r7i_processed.jpeg&w=3840&q=75)
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