Answered: 5 x 10-8 kL= ? mL be sure to show…

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Chemistry

5 x 10-8 kL= ? mL be sure to show work and report correct number of sig figs and units

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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drc%3D0&gi=24758088ctgl=18dnb 06 What is the molarity of a solution prepared by dissolving 213.6 grams of Fe(OH)3 in enough water to produce a total volume of 1.5 L? Round your answer to 1 decimal place. Your Answer: Answer units D Add attachments to support your work
DATA: Mass of potassium nitrate mass of test tube and potassium nitrate mass of test tube mass of potassium nitrate Volume of water taken Buret readings: Final gaml Initial Volume 4.97 added Temperature at which crystals appear Total volume of water in tube ML 1st addition 2nd addition 7.09ml 12.1ml 2.12 mal 7.09 ml 12.1ml 53.85839 43.9740g 9.9131 water. Record all data in the 4.97 9.98 15.78 4.97 9.98 3rd addition 17.9 ml 21.1ml 78.8 Temperature of water when volume is measured Density of water at when volume is measured (from reference) 0.970 Trial | || 52.0 39.1 21.4°C 15,18 4th addition 18.98 17.9ml ||| 28.2 18.98 IV 2
Please show your complete solution. Thank you very much! Convert 780 deg R to deg K.
PERCENT WATER IN A HYDRATE DATA/CALCULATION SHEET NAME 1.. crucible, cover, BaCl2 2H2O _\8, a0G! g crucible and cover 14.0188g BaCl 2H2O 4.1873 g first second third weighing weighing weighing crucible, cover, anhydrous BaCl, 7.5824 17.5815 H2O lost (use your last weighing) 17.58158 % water, experimental SHOW CALCULATION % water, theoretical (See prelab) % error SHOW CALCULATION
P 5 2 ✓ C Home Insert Draw Design 2- m. AutoSave OFF Paste Page 1 of 1 Calibri (Bo... v 12 B I 0 words V 4 ab X₂ V Layout A^ A x² A V References Aa ✓ Dv 1 V English (United States) Mailings Review View B-E 1¹E == number of moles of water = V Tell me A↓ Document2 3 Aa BbCcDdEe Normal AaBbCcDdEe No Spacing 4 + Aa BbCcDc AaBb CcDd E€ Aa Bb Heading 1 Heading 2 Title 5 In Part B of the experiment, a student mixes 30.0 mL of 1.1 M HCl(aq) with 30.0 mL of 1.000 M NaOH(aq) in a well-insultated calorimeter and observes that the temperature of the solution increases by 5.75 °C. These are similar conditions as the previous two problems. How many moles of water are formed? Styles Pane 6 Focus Dictate E mol |||| I Share Comments Sensitivity Editor + 220%
QUESTION 16 Match the correct choices with the given. For gravimetric analysis, use this data to answer the questions. |Trial 1 0.6020 g 24.8405 g 24.8451 g 24.8422 Trial 2 0.5021 g 22.8165 g 22.8165 g Trial 3 0.5018 g 22.8169 g 22.8169 g |Weight of Sample Weight of Crucible and Ba$O, 8 24.8422 g Constant Weight of Crucible & Sample 24.8422 g 22.8165 g 22.8169 g Weight of Crucible 24.3181 22.3593 g 22.3641 g 24.3160 g 24.3142 g 24.3142 g 24.3142 g 24.3142 g 22.3523 g 22.3534 g 22.3532 g 22.3532 g 22.3612 g 22.3605 g 22.3605 g 22.3605 g Constant Weight of Crucible 22.3532 g 22.3605 g Weight of BaSo, |% so,2- Average Standard deviation Relative standard deviation A. 2.65 Average of the % (w/w) SO42- B. to decompose the solid and form a compound of known composition and to remove the solvent and any non-volatile species Standard deviation of the % (w/w) So2- Relative standard deviation of the C. reprecipitation % (w/w) SO42- D. formation of small crystals This is a drastic but effective…
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The density or specific gravity of the liquid can be used in computing the equivalent weight of the reactant given in milliliters. A. True B. False