Electric Flux and Gauss's Law: The electric field E, at one face of a parallelepiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field E₂ is also uniform over the entire face and is directed into that face of the figure at right. The two faces in question are inclined at 30° from the horizontal, while E, and E, are both horizontal; E, has a magnitude of 2 × 104 N/C and E₂ has a magnitude of 7 x 104 N/C. a. Find the flux individually on the surface (Show it by Gauss's Law) b. Find the total flux on the surface

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Electric Flux and Gauss's Law: The electric field ₁ at one face
of a parallelepiped is uniform over the entire face and is directed
out of the face. At the opposite face, the electric field E₂ is also
uniform over the entire face and is directed into that face of the
figure at right. The two faces in question are inclined at 30° from
the horizontal, while E₁ and E₂ are both horizontal; E₁ has a
magnitude of 2 x 104 N/C and E₂ has a magnitude of 7 ×
104 N/C.
a. Find the flux individually on the surface (Show it by
Gauss's Law)
b. Find the total flux on the surface
5.00
cm
K
ر
E₁
6.00
cm
30°
Transcribed Image Text:Electric Flux and Gauss's Law: The electric field ₁ at one face of a parallelepiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field E₂ is also uniform over the entire face and is directed into that face of the figure at right. The two faces in question are inclined at 30° from the horizontal, while E₁ and E₂ are both horizontal; E₁ has a magnitude of 2 x 104 N/C and E₂ has a magnitude of 7 × 104 N/C. a. Find the flux individually on the surface (Show it by Gauss's Law) b. Find the total flux on the surface 5.00 cm K ر E₁ 6.00 cm 30°
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