Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.22 x 10¹ N/C as shown in the figure below. 30.0 cm 60.0⁰ 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. kNm²/C (b) Calculate the electric flux through the slanted surface of the box. kN. m²/C (c) Calculate the electric flux through the entire surface of the box. kN. m²/c

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### Analyzing Electric Flux Through a Closed Triangular Box

#### Problem Statement

Consider a closed triangular box resting within a horizontal electric field of magnitude \(E = 6.22 \times 10^4 \, \text{N/C}\) as shown in the figure below.

#### Diagram Description

The diagram depicts a triangular box placed in a horizontal electric field. The specified dimensions of the box are:
- Height: 10.0 cm
- Base: 30.0 cm
- Angle between the slanted surface and horizontal base: 60.0 degrees

The electric field \( \vec{E} \) is directed horizontally, depicted with orange arrows pointing from left to right.

#### Questions

(a) Calculate the electric flux through the vertical rectangular surface of the box.
\[ \text{Electric Flux} (kN \cdot m^2/C) \]

(b) Calculate the electric flux through the slanted surface of the box.
\[ \text{Electric Flux} (kN \cdot m^2/C) \]

(c) Calculate the electric flux through the entire surface of the box.
\[ \text{Electric Flux} (kN \cdot m^2/C) \]

Ensure to use the principles of electric flux calculation, considering the orientation of each surface with respect to the electric field direction.
Transcribed Image Text:### Analyzing Electric Flux Through a Closed Triangular Box #### Problem Statement Consider a closed triangular box resting within a horizontal electric field of magnitude \(E = 6.22 \times 10^4 \, \text{N/C}\) as shown in the figure below. #### Diagram Description The diagram depicts a triangular box placed in a horizontal electric field. The specified dimensions of the box are: - Height: 10.0 cm - Base: 30.0 cm - Angle between the slanted surface and horizontal base: 60.0 degrees The electric field \( \vec{E} \) is directed horizontally, depicted with orange arrows pointing from left to right. #### Questions (a) Calculate the electric flux through the vertical rectangular surface of the box. \[ \text{Electric Flux} (kN \cdot m^2/C) \] (b) Calculate the electric flux through the slanted surface of the box. \[ \text{Electric Flux} (kN \cdot m^2/C) \] (c) Calculate the electric flux through the entire surface of the box. \[ \text{Electric Flux} (kN \cdot m^2/C) \] Ensure to use the principles of electric flux calculation, considering the orientation of each surface with respect to the electric field direction.
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