Calculate the electric flux through the vertical rectangular surface of the box.

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Chapter1: Units, Trigonometry. And Vectors
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Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.26  104 N/C as shown in the figure below.

(a) Calculate the electric flux through the vertical rectangular surface of the box.

The image depicts a right-angled triangular prism with a rectangular face. The dimensions are marked as 30.0 cm along the base and 10.0 cm along the vertical side. The angle between the vertical side and the hypotenuse is 60.0°. 

An electric field, denoted by the vector \(\mathbf{E}\), is illustrated as a series of parallel orange arrows directed towards the face opposite the right angle. These arrows indicate the direction and uniformity of the electric field across the surface area.

This diagram could be used to discuss concepts related to electric fields, such as the interaction of fields with surfaces, field strength, and related calculations involving geometric dimensions and angles.
Transcribed Image Text:The image depicts a right-angled triangular prism with a rectangular face. The dimensions are marked as 30.0 cm along the base and 10.0 cm along the vertical side. The angle between the vertical side and the hypotenuse is 60.0°. An electric field, denoted by the vector \(\mathbf{E}\), is illustrated as a series of parallel orange arrows directed towards the face opposite the right angle. These arrows indicate the direction and uniformity of the electric field across the surface area. This diagram could be used to discuss concepts related to electric fields, such as the interaction of fields with surfaces, field strength, and related calculations involving geometric dimensions and angles.
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