Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.10 x 104 N/C as shown in the figure below. 30.0 cm 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. 2130 What is the direction of the normal vector for this surface? kN • m2/C (b) Calculate the electric flux through the slanted surface of the box. |-2130 You are correct that the flux is the negative of the flux through the vertical surface, but your answer for that flux is incorrect. kN - m2/C

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Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.10 x 104 N/C as shown in the figure below.
30.0 cm
60.0°
10.0 cm
(a) Calculate the electric flux through the vertical rectangular surface of the box.
2130
What is the direction of the normal vector for this surface? kN · m2/C
(b) Calculate the electric flux through the slanted surface of the box.
|-2130
You are correct that the flux is the negative of the flux through the vertical surface, but your answer for that flux is incorrect. kN · m2/c
Transcribed Image Text:Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.10 x 104 N/C as shown in the figure below. 30.0 cm 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. 2130 What is the direction of the normal vector for this surface? kN · m2/C (b) Calculate the electric flux through the slanted surface of the box. |-2130 You are correct that the flux is the negative of the flux through the vertical surface, but your answer for that flux is incorrect. kN · m2/c
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