A hemisphere with a flat circular bottom is placed in an electric field as shown in the figure. In this case E= 3.86 x 105 N/C and the radius of the hemisphere is r = 3.94 cm. r E Figure 1. This is a 2D cross section of a flat quarter sphere of radius r lying in an electric field of strength E. Part 1) What is the magnitude of the electric flux through the flat bottom of the hemisphere? $F= Nm²/C Part 2) What is the magnitude of the electric flux through the top curved surface of the hemisphere? $B= Nm²/C Part 3) What is the net flux through the entire enclosed hemisphere? ФЕ Nm²/C

A hemisphere with a flat circular bottom is placed in an electric field as shown in the figure. In this case E= 3.86 x 105 N/C and the radius of the hemisphere is r = 3.94 cm. r E Figure 1. This is a 2D cross section of a flat quarter sphere of radius r lying in an electric field of strength E. Part 1) What is the magnitude of the electric flux through the flat bottom of the hemisphere? $F= Nm²/C Part 2) What is the magnitude of the electric flux through the top curved surface of the hemisphere? $B= Nm²/C Part 3) What is the net flux through the entire enclosed hemisphere? ФЕ Nm²/C

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

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In which of the following contexts can Gausss law not be readily applied to find the electric field? (a) near a long, uniformly charged wire (b) above a large, uniformly charged plane (c) inside a uniformly charged ball (d) outside a uniformly charged sphere (e) Gausss law can be readily applied to find the electric field in all these contexts.
A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108 C is placed on the plate. Find (a) the charge density on each face of the plate, (b) the electric field just above the plate, and (c) the electric field just below the plate. You may assume the charge density is uniform.
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A positively charged sphere and a negatively charged sphere are in a sealed container. The only way the charged spheres can be examined is by observing the electric field outside the container. a. Given the depiction of the electric fields in Figure P25.7A, is the net electric flux through the container zero, positive, or negative? Explain your answer. b. Two different spheres are placed inside a container. Given the depiction of the electric fields in Figure P25.7B, is the net electric flux through the container zero, positive, or negative? Explain your answer.
A hollow, metallic, spherical shell has exterior radius 0.750 m, carries no net charge, and is supported on an insulating stand. The electric field everywhere just outside its surface is 890 N/C radially toward the center of the sphere. Explain what you can conclude about (a) the amount of charge on the exterior surface of the sphere and the distribution of this charge, (b) the amount of charge on the interior surface of the sphere and its distribution, and (c) the amount of charge inside the shell and its distribution.
A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 124.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by E = (3.00 + 2.00x2)i N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. (b) What net charge enclosed by the surface?
The Electric Flux and Gauss’ Law A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60° to a uniform electric field of magnitude 14 N/C. A) Find the magnitude of the electric flux through the sheet. B) Does the answer to part (A) depend on the shape of the sheet? Why or why not? C) For what angle ϕ between the normal to the sheet and the electric field is the magnitude of the flux through the sheet (i) largest and (ii) smallest?
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Part A A spherically symmetric charge distribution produces the electric field É = (250/r) î N/C, where r is in m What is the electric field strength at r = 21.0 cm? ? E = N/C Submit Request Answer Part B What is the electric flux through a 16.0-cm-diameter spherical surface that is concentric with the charge distribution? Nm²/C Submit Request Answer Part C How much charge is inside this 16.0-cm-diameter spherical surface? VO AEO Q = nC Submit Request Answer
Part A The three parallel planes of charge shown in the figure (Figure 1)have surface charge densities 7, 1. and Find the magnitude of the electric field in region 1. nνα ΑΣφ Submit Request Answer Part B What is the direction of the electric field in region 1? O Upward O Downward O The field is zero Submit Request Answer Part C Find the magnitude of the electric field in region 2. ? Submit Request Answer Part D What is the direction of the electric field in region 2? O Upward O Downward O The field is zero Figure 1 of 1 Submit Request Answer 7 ++++++++++++++++++ Part E Find the magnitude of the electric field in region 3. P Pearson in