Each of the four trials can be used to calculate k and then the four results can be averaged. We will use Trial 4 to determine the rate constant in this example. What is the value of the rate constant? [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.420 0.733 0.0145 Trial 2 0.840 0.733 0.0579 Trial 3 0.420 1.47 0.0290 Trial 4 0.827 0.710 0.0544 Rate = k[A]°[B]! X L/mol•min Recheck Next (5 of 5) 8th attempt

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Now that the order for both reactants is known, the rate constant, k, can be determined.

Each of the four trials can be used to calculate k and then the four results can be averaged.

We will use Trial 4 to determine the rate constant in this example.

What is the value of the rate constant?

Now that the order for both reactants is known, the rate constant, k, can be determined.
Each of the four trials can be used to calculate k and then the four results can be averaged.
We will use Trial 4 to determine the rate constant in this example.
What is the value of the rate constant?
[A], mol/L [B], mol/L rate, mol/(L-min)
Trial 1 0.420
0.733
0.0145
Trial 2 0.840
0.733
0.0579
Trial 3 0.420
1.47
0.0290
Trial 4 0.827
0.710
0.0544
Rate = k[A]°[B]!
X L'mol•min
Recheck
Next (5 of 5)
8th attempt
Transcribed Image Text:Now that the order for both reactants is known, the rate constant, k, can be determined. Each of the four trials can be used to calculate k and then the four results can be averaged. We will use Trial 4 to determine the rate constant in this example. What is the value of the rate constant? [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.420 0.733 0.0145 Trial 2 0.840 0.733 0.0579 Trial 3 0.420 1.47 0.0290 Trial 4 0.827 0.710 0.0544 Rate = k[A]°[B]! X L'mol•min Recheck Next (5 of 5) 8th attempt
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