6. Given: 2NO(g) + Br,(g) 2NOBr(g) Rate ( M min -') 1.1 X 10 -2 [NO] [Br.] 1 1 2 1 4.5 X 10-2 4 1.8 X 10 Determine the reaction rate law and the rate constant

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6. Given: 2NO(g) + Br,(g) I 2NOBr(g)
Rate ( M min ')
1. 1 X 10 -2
4.5 X 10-2
1.8 X 10-
[NO]
[Br,]
1
1
1
4
2
Determine the reaction rate law and the rate constant
Transcribed Image Text:6. Given: 2NO(g) + Br,(g) I 2NOBr(g) Rate ( M min ') 1. 1 X 10 -2 4.5 X 10-2 1.8 X 10- [NO] [Br,] 1 1 1 4 2 Determine the reaction rate law and the rate constant
Expert Solution
Step 1

Rate law can be written as

rate(r) = k [NO]a[Br2]b

Where, k= rate constant; a and b are the order of the reaction with respect to NO and Br2 respectively

Putting the values from the given table we get

 1.1×10-2=k(1)a(1)b k = 1.1×10-2Putting the second set of values we get4.5×10-2=k(2)a(1)b(2)a=4.5×10-21.1×10-22a=4.09Since 4.09 is very close to 4, so we can write 2a=42a=22a = 2Using the third set set of values we get1.8×10-1=1.1×10-2(4)2(2)b2b=2b=1

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