E1.4 The cross section of a stream can be approximated by the compound chan- nel shown in figure 1. The bottom slope is So = 0.0009. The Manning roughness factor n = 0.025 for the main channel and n = 0.035 for the overbank areas. Determine the normal depth for a discharge of 197m3/s. Also calculate the energy coefficient a and the momentum coefficient ß for the channel with this flow condition. n = 0.035 n = 0.035 1 Yn 4.5m n = 0.025 7m 2m I 10m 2m 7m Figure 1: A Compound section

E1.4 The cross section of a stream can be approximated by the compound chan- nel shown in figure 1. The bottom slope is So = 0.0009. The Manning roughness factor n = 0.025 for the main channel and n = 0.035 for the overbank areas. Determine the normal depth for a discharge of 197m3/s. Also calculate the energy coefficient a and the momentum coefficient ß for the channel with this flow condition. n = 0.035 n = 0.035 1 Yn 4.5m n = 0.025 7m 2m I 10m 2m 7m Figure 1: A Compound section

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.

Question

E1.4 The cross section of a stream can be approximated by the compound chan-
nel shown in figure 1. The bottom slope is So
roughness factor n = 0.025 for the main channel and n = 0.035 for the
overbank areas. Determine the normal depth for a discharge of 197m3/s.
Also calculate the energy coefficient a and the momentum coefficient ß for
the channel with this flow condition.
0.0009. The Manning
n = 0.035
1
3
n = 0.035
2
Yn
4.5m
n = 0.025
2m
2m
7m
10m
7m
Figure 1: A Compound section
(Answer: yn = 5.5m, a =
3.3, B = 1.97.)

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