Prob. # S (a): In a partially flowing channel having a isosceles- ngular cross section as shown below (Figure 5a), the rate of flow can be expressed as Q=KAR 23, where k is a constant and A and R are respectively cross sectional area and the hydraulic radius. Determine the depth at which the discharge is maximum. For the channel, A= [B- (h/3)]h, and P= B + (4h/3). A Figure 5a-Triangular channel cross section.

Prob. # S (a): In a partially flowing channel having a isosceles- ngular cross section as shown below (Figure 5a), the rate of flow can be expressed as Q=KAR 23, where k is a constant and A and R are respectively cross sectional area and the hydraulic radius. Determine the depth at which the discharge is maximum. For the channel, A= [B- (h/3)]h, and P= B + (4h/3). A Figure 5a-Triangular channel cross section.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.

Question

Prob. # 5 (a): In a partially flowing channel having a isosceles-triangular cross section as shown
below (Figure 5a), the rate of flow can be expressed as Q=KAR 2³, where k is a constant and A
and R are respectively cross sectional area and the hydraulic radius. Determine the depth at which
the discharge is maximum. For the channel, A= [B - (h/√3)]h, and P= B + (4h/3).
60
60°
Figure
section.
5a-Triangular channel cross

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