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Question-1 Hydraulic Engineering (Open Channel Hydraulics) Water is flowing in the trapezoidal channel shown below. The critical depth, y, for such a channel must satisfy the equation; -L Q² 84³ 1- -L=0 Where Q = flow rate = 20 m³/s g = gravitational acceleration = 9.81 m/s² L = width of water at the channel surface (in meter) A = the cross-sectional area (in square meter). A=3y+1.2y² L and A can be related to the depth, y, as; L=3+2.4y Determine the critical depth, y. Use Bisection method with &s = 0.1%.

Question-1 Hydraulic Engineering (Open Channel Hydraulics) Water is flowing in the trapezoidal channel shown below. The critical depth, y, for such a channel must satisfy the equation; -L Q² 84³ 1- -L=0 Where Q = flow rate = 20 m³/s g = gravitational acceleration = 9.81 m/s² L = width of water at the channel surface (in meter) A = the cross-sectional area (in square meter). A=3y+1.2y² L and A can be related to the depth, y, as; L=3+2.4y Determine the critical depth, y. Use Bisection method with &s = 0.1%.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question-1 Hydraulic Engineering (Open Channel Hydraulics) Water is flowing in the trapezoidal channel shown below. The critical depth, y, for such a channel must satisfy the equation; -L 101=0 Where Q = flow rate = 20 m³/s g = gravitational acceleration = 9.81 m/s² L = width of water at the channel surface (in meter) A = the cross-sectional area (in square meter). A=3y+1.2y² L and A can be related to the depth, y, as; L = 3+2.4y Determine the critical depth, y. Use Bisection method with &s = 0.1%.
Transcribed Image Text:Question-1 Hydraulic Engineering (Open Channel Hydraulics) Water is flowing in the trapezoidal channel shown below. The critical depth, y, for such a channel must satisfy the equation; -L 101=0 Where Q = flow rate = 20 m³/s g = gravitational acceleration = 9.81 m/s² L = width of water at the channel surface (in meter) A = the cross-sectional area (in square meter). A=3y+1.2y² L and A can be related to the depth, y, as; L = 3+2.4y Determine the critical depth, y. Use Bisection method with &s = 0.1%.
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