A trapezoidal channel with uniform flow depth 4 m. The base width is 6 m and the side slopes are equal to (1V:1H), Manning's n can be taken as shown in the figure. What is the weighted Manning's coefficient using Horton's equation. n=0.019 1=0.022/1 1 n=0.012
A trapezoidal channel with uniform flow depth 4 m. The base width is 6 m and the side slopes are equal to (1V:1H), Manning's n can be taken as shown in the figure. What is the weighted Manning's coefficient using Horton's equation. n=0.019 1=0.022/1 1 n=0.012
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![A trapezoidal channel with uniform flow
depth 4 m. The base width is 6 m and the
side slopes are equal to (1V:1H),
Manning's n can be taken as shown in the
figure. What is the weighted Manning's
coefficient using Horton's equation.
n30.019
n=0.022,
1
1
n=0.012
.a
0.017
.b
0.025
.C
0.033
.d
none of these](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ceb3fdd-28f4-49a3-91b2-0d9a939ea942%2F40e74591-9070-4578-b106-7930f6fd377f%2Fgyeqe6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A trapezoidal channel with uniform flow
depth 4 m. The base width is 6 m and the
side slopes are equal to (1V:1H),
Manning's n can be taken as shown in the
figure. What is the weighted Manning's
coefficient using Horton's equation.
n30.019
n=0.022,
1
1
n=0.012
.a
0.017
.b
0.025
.C
0.033
.d
none of these
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