e shear strength of each of ten test spot welds is determined, yielding the following data (psi). 373 415 375 358 409 371 397 389 362 367 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) average 381.6 V psi standard deviation 19.84 x psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of p and o? Now use the invariance principle.] (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X S 400). [Hint: P(X S 400) = 0((400 - u)/o).] (Round your answer to four decimal places.)

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**The Shear Strength of Test Spot Welds**

The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 

373, 415, 375, 358, 409, 371, 397, 389, 362, 367

**(a)** Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two decimal places.)

- **Average:** 381.6 psi
- **Standard Deviation:** 19.84 psi

**(b)** Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of μ and σ? Now use the invariance principle.] (Round your answer to two decimal places.)

- Estimated strength value: ____ psi

**(c)** Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the MLE of P(X ≤ 400). [Hint: P(X ≤ 400) = Φ((400 − μ)/σ).] (Round your answer to four decimal places.)

- Probability estimate: ____

This exercise involves understanding the concepts of mean, standard deviation, normal distribution, and probability estimation in the context of shear strength testing. The method of maximum likelihood is used to estimate parameters, and percentile calculation is applied for determining thresholds.
Transcribed Image Text:**The Shear Strength of Test Spot Welds** The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 373, 415, 375, 358, 409, 371, 397, 389, 362, 367 **(a)** Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) - **Average:** 381.6 psi - **Standard Deviation:** 19.84 psi **(b)** Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of μ and σ? Now use the invariance principle.] (Round your answer to two decimal places.) - Estimated strength value: ____ psi **(c)** Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the MLE of P(X ≤ 400). [Hint: P(X ≤ 400) = Φ((400 − μ)/σ).] (Round your answer to four decimal places.) - Probability estimate: ____ This exercise involves understanding the concepts of mean, standard deviation, normal distribution, and probability estimation in the context of shear strength testing. The method of maximum likelihood is used to estimate parameters, and percentile calculation is applied for determining thresholds.
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