Consider the following n = 11 observations on shear strength of a joint bonded in a particular manner (Exi = 514.90): 4.4 16.4 22.2 30.0 33.1 36.6 40.4 66.7 73.7 81.5 109.9 Determine the value of the 14% trimmed mean given the following (express your answer to 3 decimal places: x.XXx): Mean 46.809 9.09% trimmed mean (1/11) 44.511 18.18% trimmed mean (2/11) 43.243 Median 36 600

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### Analysis of Shear Strength Data for Joint Bonding

The following data represents 11 observations on the shear strength of a joint bonded in a particular manner, with a sum of all observations (ΣXi) equal to 514.90:

**Observations:**
- 4.4
- 16.4
- 22.2
- 30.0
- 33.1
- 36.6
- 40.4
- 66.7
- 73.7
- 81.5
- 109.9

#### Statistical Measures:
The objective is to determine the value of the 14% trimmed mean, given the detailed statistical measures already provided:

- **Mean (µ):** The arithmetic average of the observations:
  \[
  \text{Mean} = 46.809
  \]

- **9.09% Trimmed Mean (1/11):** The mean calculated after removing the lowest and highest 9.09% of data points:
  \[
  9.09\% \text{ trimmed mean} = 44.511
  \]

- **18.18% Trimmed Mean (2/11):** The mean calculated after removing the lowest and highest 18.18% of data points:
  \[
  18.18\% \text{ trimmed mean} = 43.243
  \]

- **Median:** The middle value of the data set when arranged in ascending order:
  \[
  \text{Median} = 36.600
  \]

#### Calculating the 14% Trimmed Mean:
To calculate the 14% trimmed mean, 14% of the total number of observations (n = 11) needs to be calculated. Since 14% of 11 is approximately 1.54, we trim the data by removing the lowest and highest values, so approximately one value from each end can be trimmed.

Detailed steps:
1. **Sort the Data:**
   \[
   \{4.4, 16.4, 22.2, 30.0, 33.1, 36.6, 40.4, 66.7, 73.7, 81.5, 109.9\}
   \]

2. **Remove the Lowest and Highest Approximate 1.54 Values:**
Transcribed Image Text:### Analysis of Shear Strength Data for Joint Bonding The following data represents 11 observations on the shear strength of a joint bonded in a particular manner, with a sum of all observations (ΣXi) equal to 514.90: **Observations:** - 4.4 - 16.4 - 22.2 - 30.0 - 33.1 - 36.6 - 40.4 - 66.7 - 73.7 - 81.5 - 109.9 #### Statistical Measures: The objective is to determine the value of the 14% trimmed mean, given the detailed statistical measures already provided: - **Mean (µ):** The arithmetic average of the observations: \[ \text{Mean} = 46.809 \] - **9.09% Trimmed Mean (1/11):** The mean calculated after removing the lowest and highest 9.09% of data points: \[ 9.09\% \text{ trimmed mean} = 44.511 \] - **18.18% Trimmed Mean (2/11):** The mean calculated after removing the lowest and highest 18.18% of data points: \[ 18.18\% \text{ trimmed mean} = 43.243 \] - **Median:** The middle value of the data set when arranged in ascending order: \[ \text{Median} = 36.600 \] #### Calculating the 14% Trimmed Mean: To calculate the 14% trimmed mean, 14% of the total number of observations (n = 11) needs to be calculated. Since 14% of 11 is approximately 1.54, we trim the data by removing the lowest and highest values, so approximately one value from each end can be trimmed. Detailed steps: 1. **Sort the Data:** \[ \{4.4, 16.4, 22.2, 30.0, 33.1, 36.6, 40.4, 66.7, 73.7, 81.5, 109.9\} \] 2. **Remove the Lowest and Highest Approximate 1.54 Values:**
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