The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.88 mils. Assuming normality, derive a 95% CI for ?2 and for ?. (Round your answers to two decimal places.) CI for ?2 (________ , _______) mils2 CI for ? (________ , _______) mils
The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.88 mils. Assuming normality, derive a 95% CI for ?2 and for ?. (Round your answers to two decimal places.) CI for ?2 (________ , _______) mils2 CI for ? (________ , _______) mils
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.88 mils. Assuming normality, derive a 95% CI for ?2 and for ?. (Round your answers to two decimal places.)
CI for ?2 |
(________ , _______) mils2
|
CI for ? |
(________ , _______) mils
|
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