The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.85 mils. Assuming normality, derive a 95% CI for o2 and for a. (Round your answers to two decimal places.) CI for a? mils2

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.85 mils. Assuming normality, derive
a 95% CI for oʻ and for o. (Round your answers to two decimal places.)
CI for o?
mils?
CI for o
mils
Transcribed Image Text:The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.85 mils. Assuming normality, derive a 95% CI for oʻ and for o. (Round your answers to two decimal places.) CI for o? mils? CI for o mils
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