The figure below shows a frequency and relative-frequency distribution for the heights of female students attending a college. Records show that the mean height of these students is 64.5 inches and that the standard deviation is 1.8 inches. Use the given information to complete parts (a) through (c). a. The area under the normal curve with parameters H = 64.5 and o = 1.8 that lies to the left of 63 is 0.2100. Use this information to estimate the percent of female students who are shorter than 63 inches. (Type an integer or a decimal. Do not round.) Frequency Height (in.) Relative freq. 9 60-under 61 0.0070 61-under 62 9. 0.0314 62-under 63 25 0.0871 63-under 64 62 0.2160 64-under 65 94 0.3275 65-under 66 62 0.2160 66-under 67 25 0.0871 67-under 68 0.0209 68-under 69 0.0070 287 1.0000

The figure below shows a frequency and relative-frequency distribution for the heights of female students attending a college. Records show that the mean height of these students is 64.5 inches and that the standard deviation is 1.8 inches. Use the given information to complete parts (a) through (c). a. The area under the normal curve with parameters H = 64.5 and o = 1.8 that lies to the left of 63 is 0.2100. Use this information to estimate the percent of female students who are shorter than 63 inches. (Type an integer or a decimal. Do not round.) Frequency Height (in.) Relative freq. 9 60-under 61 0.0070 61-under 62 9. 0.0314 62-under 63 25 0.0871 63-under 64 62 0.2160 64-under 65 94 0.3275 65-under 66 62 0.2160 66-under 67 25 0.0871 67-under 68 0.0209 68-under 69 0.0070 287 1.0000

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Sketch a standard normal curve and shade the area that lies to the right of a. - 1.02, b. 0.6, c. 0,…

Q: 5. Diastolic blood pressures are assumed to follow a normal distribution with a mean of 85 and a…

Q: The Law Enforcement Management and Administrative Statistics (LEMAS) survey reports that the mean…

A: Mean=1.99s=0.84

Q: The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates.…

A: From the provided information, The table can be constructed as: Mid value (x) Frequency (f)…

Q: A simple linear regression that describes the effect of individuals’ cigarette smoking on health is…

A: Introduction: The regression coefficient depends on the change of scale of the response, as well as…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: Normal distribution is a continuous distribution which has many real life applications. Normal curve…

Q: The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates.…

A: Given : The frequency distribution was obtained using a class width of 0.5 . Given data represents…

Q: Assume that a randomly selected subject is given a bone density test. Bone density test scores are…

A: To solve this problem, we need to find the 17th percentile (P17) of a normally distributed dataset…

Q: Dr. Hill, a physical therapist, compared the average length of office visits for his male and female…

A: Here, mean1 is 5.9 and mean2 is 6.3. Standard deviations are 2.2 and 1.7. Sample numbers are 7 for…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: From the provided information, Mean (µ) = 100 Standard deviation (σ) = 15 X~N (100, 15)

Q: A test is scaled so that the mean score is 490 and the standard deviation is 100. What percentage of…

A: Given information μ=490 And σ=100 We have to find the percentage of students taking this test should…

Q: Sketch a standard normal curve and shade the area that lies to the right of a. - 1.03, b. 0.6, c. 0,…

Q: 5. Losses X follow a paralogistic distribution with 0 =5000 and a = 3. An insurance coverage for X…

A: Given : θ = 5000α = 3

Q: The are an average of 12 hairs found in fast food per month with a standard deviation of 2 hairs.…

A: It is given that the mean and standard deviation are 12 and 2.

Q: The scores on a mathematics exam have a mean of 70 and a standard deviation of 7. Find the x-value…

A: given data μ = 70σ = 7Z = -1.28X = ?

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Step 1: Sketch the regionSince we are making a graph for a bone density test score between -2.05 and…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: normal distribution μ = 100σ = 15P(75<x<110) = ?

Q: Dr. Lorenzo finds that his patients' heart rates are normally distributed, with an average of 69…

A: The normal distribution has mean = 69 beats and has the standard deviation = 6 beats.

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

Q: A. Directions: Find the area under the normal curve of the following z values, then sketch the…

A: Note: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts…

Q: a. pH levels between 7.00 and 7.50. b. pH levels over 7.32. Click here to view page 1 of the…

A: Given : pH level of arterial cord is normally distributed with " Mean , μ = 7.24 Standard deviation…

Q: Use the frequency distribution to construct a histogram. Does the histogram appear to depict data…

A: Use the frequency distribution to construct a histogram. Weight (g) Frequency 6.000-6.049 3…

Q: Use a z-table to find the specified area. Between the mean and 2.41 deviations from the mean…

A: Given: Deviation from mean = 2.41 As z table has to be used, so mean of the distribution is 0.

Q: Sketch a standard normal curve and shade the area that lies to the right of a. - 1.03, b. 0.6, c. 0,…

A: A continuous random variable Z is said to follow Standard Normal distribution if its probability…

Q: Section 2. Assume again that you are a wildlife biologist studying morphological cha turtles. Now…

A: Sample size n=36Sample mean=99Sample standard deviation=16

Q: Find the z-score that best satisfies the condition. This problem can be solved using technology or…

A: Ans#- Find the z-score of the given standard normal curve. P(Z < z) = 30% = 0.30

Q: A vertical line drawn through a normal distribution at z = +1.10 separates the distribution into two…

A: The value of Z ~N(0,1) , and is usually represented as, Z=X-μσ Now, using this form, a Z-table is…

Q: In a study on infants, one of the characteristics measured was head circumference. The mean head…

A: Note- Since you have posted a question with multiple sub-parts, we will solve the first three…

Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!

Question

The figure below shows a frequency and
relative-frequency distribution for the heights of female
students attending a college. Records show that the
mean height of these students is 64.5 inches and that the
standard deviation is 1.8 inches. Use the given
information to complete parts (a) through (c).
a. The area under the normal curve with parameters
H = 64.5 and o = 1.8 that lies to the left of 63 is 0.2100.
Use this information to estimate the percent of female
students who are shorter than 63 inches.
(Type an integer or a decimal. Do not round.)
Frequency
Height (in.)
Relative freq. O
f
60-under 61
2
0.0070
61-under 62
9.
0.0314
62-under 63
25
0.0871
63-under 64
62
0.2160
64-under 65
94
0.3275
65-under 66
62
0.2160
66-under 67
25
0.0871
67-under 68
0.0209
68-under 69
0.0070
287
1.0000

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Continuous Probability Distribution$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

The Law Enforcement Management and Administrative Statistics (LEMAS) survey reports that the mean number of municipal police per 1,000 local residents in U.S. cities with populations of 100,000 or more was 1.99 (s = .84). One department had 1.51 police per 1,000 residents. Convert this raw score to a z score. Find the area between the mean and z Find the area in the tail of the distribution beyond z.
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find Pg, the 6th percentile. This is the bone density score separating the bottom 6% from the top 94%. Which graph represents Pe? Choose the correct graph below. O A. OB. OP. The bone density score corresponding to Pe is. (Round to two decimal places as needed.)
A gear has been designed to have a diameter of 4 inches. The standard deviation of the process is 0.4 inch. A control chart is shown. Each chart has horizontal lines drawn at the mean, μ, ±2, and at ± 3o. Determine if the process shown is in control or out of control. Explain. Diameter (inches) Gears G Is the process in control or out of control? Select all that apply. A. Out of control, because there are nine consecutive points either above or below the mean. B. In control, because none of the three warning signals detected a change. C. Out of control, because two out of three consecutive points lie more than two standard deviations from the mean. D. Out of control, because a point lies more than three standard deviations beyond the mean. 0 1 2 3 4 5 6 7 8 9 10 11 Observation number Clear all Check answer
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 102 130 The area of the shaded region is. (Round to four decimal places as needed.)
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation Compare these results to the actual mean µ = $1.667 and standard deviation o=$1.073. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed) The population standard deviation is $ (Round to three decimal places as needed.) Compare these results to the values found using the actual data. OA. The grouped values are both slightly larger. OB. The grouped values are both slightly smaller. OC. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. OD. The grouped mean is slightly smaller, while the grouped standard deviation is slightly larger. Frequency distribution of cigarette tax rates Tax Rate 0.00 0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99…
Suppose students who enter kindergarten at Sotomayor Elementary School take a standardized vocabulary assessment. The scores on the vocabulary assessment produce a normal density curve as shown. From the graph shown, estimate the mean, median, and standard deviation of the vocabulary assessment. mean = 215 median = 215 standard deviation = | 188 215 242
Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with a mean of 0 and a standard deviation of 1. the area of the shaded region is?
Answer these questions
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. a. The area of the shaded region is (Round to four decimal places as needed.)
The histogram below describes the distribution of weights (in lbs) of 35 children age 9-10 from a local elementary school. ps://canvas.ucsc.edu/courses/49913/quizzes/69575/take?preview=1 5/23, 12:01 PM fouanbau 10- 8- 6 4- 2- 30 60 Weight in lbs The third quartile weight of these children is... 40 Quiz: Final Exam - on-line portion 50 70 80 90 100 110 3/7
Please show work
Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.