Please answer the following question and show work P1. Consider the following sample of observations on coating thickness for low viscosityPaint: .83 .88 .88 1.04 1.09 1.12 1.29 1.31 1.48 1.49 1.59 1.62 1.65 1.71 1.76 1.83a. Calculate a point estimate of the mean value of coatingthickness, and state which estimator you used. Calculate a point estimate of the median of the coatingthickness distribution, and state which estimatoryou used.b. Calculate a point estimate of the value that separates the largest 25% of all values in the thicknessdistribution from the remaining 75%, and state which estimator you used. Also estimate P(X < 1.5), i.e.,the proportion of all thickness values less than 1.5.c. Please draw a normal probability plot and see if it supports the assumption of normal distribution.

Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case you require the unanswered parts also, kindly re-post that parts separately. a. Point estimate of the mean value of coating thickness: Point Estimate=sum of valuesNumber of values =0.83+0.88+0.88+.....+1.76+1.8316 =1.3481 Sample mean is used as the point estimate of the mean value of coating thickness. Point estimate of the Median value of coating thickness: Let us arrange the data in ascending order: 0.83 0.88 0.88 1.04 1.09 1.12 1.29 1.31 1.48 1.49 1.59 1.62 1.65 1.71 1.76 1.83 Median=sum of the middle two values2 =1.31+1.482 =1.395 Sample median is used as the point estimate of the median value of coating thickness. Consider, the point estimate of standard deviation: SD=1n-1∑xi-x¯2 =0.3385 The point estimate of the value that separates the largest 25% of all values in the thickness distribution from the remaining 75%: PX>x=25%PX-meanstandard deviation>x-meanstandard deviation=0.251-Pz≤x-1.34810.3385=0.25Pz≤x-1.34810.3385=0.75x-1.34810.3385=0.6745 x=1.5764 Thus, the point estimate of the value that separates the largest 25% of all values in the thickness distribution from the remaining 75% is 1.5764.