402 360 389 364 415 375 367 409 362 358 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using decimal places.) average psi standard deviation psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 9 (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X s 400). decimal places.)
402 360 389 364 415 375 367 409 362 358 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using decimal places.) average psi standard deviation psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 9 (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X s 400). decimal places.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The shear strength of each of ten test spot welds is determined, yielding the following data (psi).
402
360
389
364
415
375
367
409
362
358
(a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two
decimal places.)
average
psi
standard deviation
psi
(b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of µ and o? Now use the invariance principle.]
(Round your answer to two decimal places.)
psi
(c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X < 400). [Hint: P(X < 400) = ¤((400 – µ)/).] (Round your answer to four
decimal places.)
You may need to use the appropriate table in the Appendix of Tables to answer this question.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F704a64b5-5250-41d0-9c29-5aaf5a50e535%2F576a5cfd-9668-469e-a192-c771139cbff6%2Fphaqf6r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The shear strength of each of ten test spot welds is determined, yielding the following data (psi).
402
360
389
364
415
375
367
409
362
358
(a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two
decimal places.)
average
psi
standard deviation
psi
(b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of µ and o? Now use the invariance principle.]
(Round your answer to two decimal places.)
psi
(c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X < 400). [Hint: P(X < 400) = ¤((400 – µ)/).] (Round your answer to four
decimal places.)
You may need to use the appropriate table in the Appendix of Tables to answer this question.
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